如何使用 AssertJ 测试列表是否已排序

Question

给定

List<Integer> list = ...

我想用 AssertJ 测试它是否已排序。就像是：

assertThat(list).isSorted()

是否可以？

Answer 1

AssertJ 提供开箱isSorted()即isSortedAccordingTo(Comparator)用的列表断言：

List<String> strings = List.of("abc", "DEF");

assertThat(strings).isSorted(); // fails as "abc" is after "DEF" lexicographically
assertThat(strings).isSortedAccordingTo(String.CASE_INSENSITIVE_ORDER); // succeeds