JavaScript：如何做出永远不会解决或拒绝的承诺

Question

我在用：

 await Promise.race([promise1, promise2]);

逻辑是如果promise1在 5 秒内没有解决/拒绝，那么promise2也许能够解决。因此，在延迟promise2尝试执行其操作后，如果失败，我希望promise2返回一个Promise永远无法解决的问题，以便一切都取决于等待promise1。

我试过

async function promise2(timeout=5000) {
    await new Promise(resolve => setTimeout(resolve, timeout));
    if (didStuffAndOK())  {
        return "OK"
    }
    return new Promise( () => {} )
}

return new Promise( () => {} )似乎被解释为承诺被拒绝而不是从未得到解决。

如何做出一个空洞的承诺（不是在现实生活中，而是在 JavaScript 中）？

Answer 1

直接回答你的问题new Promise( () => {} )永远不会解决。

这是教授：

new Promise(()=>{})
   .then(()=> console.log('promise resolved'))
   .catch(()=>console.log('promise rejected'));
console.log('FOO, so that you can see that the code was executed');

但我想你有不同的问题。

The logic is if promise1 has not resolved/rejected within 5s, then promise2 
might be able to resolve. So after a delay promise2 tries to do its thing, if it 
fails I wish to have promise2 return a Promise that never resolves so that its 
all up to waiting for promise1.

为此，您可以在 中解决promise2，promise1因为 Promise 是可链接的。

The logic is if promise1 has not resolved/rejected within 5s, then promise2 
might be able to resolve. So after a delay promise2 tries to do its thing, if it 
fails I wish to have promise2 return a Promise that never resolves so that its 
all up to waiting for promise1.