通过API获取YouTube用户的完整播放列表

Question

所以,这是获取youtube用户的公共播放列表的代码:

function getyoutubeplaylists($userName) {
$yt = connectyoutube();
$yt->setMajorProtocolVersion(2);
$playlistListFeed = $yt->getPlaylistListFeed($userName);
foreach ($playlistListFeed as $playlistListEntry) {
    $playlist['title'] = $playlistListEntry->title->text;
    $playlist['id'] = $playlistListEntry->getPlaylistID();
    $playlists[] = $playlist;
    $playlistVideoFeed = $yt->getPlaylistVideoFeed($playlistListEntry->getPlaylistVideoFeedUrl());
    foreach ($playlistVideoFeed as $videoEntry) {
        $playlist_assignment['youtube_id'] = substr($videoEntry->getVideoWatchPageUrl(),31,11);
        $playlist_assignment['id'] = $playlist['id'];
        $playlist_assignments[] = $playlist_assignment;
    }
}
$everything['playlists'] = $playlists;
$everything['playlist_assignments'] = $playlist_assignments;
return $everything;
}

问题是,这只会得到第一页或结果.关于如何使用Zend Gdata检索下一页结果的任何想法？

原始gdata XML显示了所需的URL:

<link rel="self" type="application/atom+xml" href="http://gdata.youtube.com/feeds/api/users/pennstate/playlists?start-index=1&amp;max-results=25"/>
<link rel="next" type="application/atom+xml" href="http://gdata.youtube.com/feeds/api/users/pennstate/playlists?start-index=26&amp;max-results=25"/>

但是,getPlaylistListFeed似乎没有任何参数来指定"start-index"或"max-results".

Answer 1

听起来您想遵循有关分页的开发指南示例。