将NSPredicate与String匹配

Question

我有这个谓词,它运作得很好.

NSPredicate *filter = [NSPredicate predicateWithFormat:@"code contains[cd] %@", predicateFilter];

所以,如果predicateFilter是112,此找到所有code有112它.我希望它能找到所有与BEGIN相关的代码112.

编辑:

我有这个谓词,我怎样才能使它的代码介于以predicateFilterStart开头的代码和以PredicateFilterEnd开头的代码之间？

NSPredicate *filterPredicate = [NSPredicate predicateWithFormat:@"ANY code BETWEEN %@",
                     [NSArray arrayWithObjects: 
                      [NSExpression expressionForConstantValue: [NSNumber numberWithFloat: [self.predicateFilterStart floatValue]]],
                      [NSExpression expressionForConstantValue: [NSNumber numberWithFloat: [self.predicateFilterEnd floatValue]]],
                      nil]];

Answer 1

NSPredicate *filter = [NSPredicate predicateWithFormat:@"code beginswith[cd] %@", predicateFilter];

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