Ziz*_*zou 0 r transform percentage dataframe
我有几个包含每月数据的数据框,我想找到每个产品和每个月的百分比分布。我对几个月的多列有问题。目前,我只能获得一个月内按组划分的百分比。
data <- data.frame(group = rep(LETTERS[1:3], each = 4),
Product = letters[1:4],
January = sample(1:100,12),
February = sample(1:100,12))
data_new1 <- transform(data,
perc = ave(January,
group,
FUN = prop.table))
data_new1$perc<-round(data_new1$perc, 2)
> data_new1
group Product January February perc
1 A a 12 16 0.05
2 A b 73 75 0.32
3 A c 78 11 0.34
4 A d 65 35 0.29
5 B a 86 63 0.36
6 B b 33 71 0.14
7 B c 92 49 0.38
8 B d 30 60 0.12
9 C a 91 59 0.37
10 C b 31 45 0.12
11 C c 99 7 0.40
12 C d 28 50 0.11
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整洁宇宙
library(dplyr)
data %>%
group_by(group) %>%
mutate(across(c("January", "February"), proportions, .names = "{.col}_perc")) %>%
ungroup()
# A tibble: 12 x 6
group Product January February January_perc February_perc
<chr> <chr> <int> <int> <dbl> <dbl>
1 A a 49 40 0.426 0.252
2 A b 1 3 0.00870 0.0189
3 A c 19 50 0.165 0.314
4 A d 46 66 0.4 0.415
5 B a 61 82 0.218 0.285
6 B b 88 51 0.314 0.177
7 B c 32 75 0.114 0.260
8 B d 99 80 0.354 0.278
9 C a 6 31 0.0397 0.373
10 C b 8 5 0.0530 0.0602
11 C c 92 20 0.609 0.241
12 C d 45 27 0.298 0.325
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根据
library(dplyr)
data %>%
group_by(group) %>%
mutate(across(c("January", "February"), proportions, .names = "{.col}_perc")) %>%
ungroup()
# A tibble: 12 x 6
group Product January February January_perc February_perc
<chr> <chr> <int> <int> <dbl> <dbl>
1 A a 49 40 0.426 0.252
2 A b 1 3 0.00870 0.0189
3 A c 19 50 0.165 0.314
4 A d 46 66 0.4 0.415
5 B a 61 82 0.218 0.285
6 B b 88 51 0.314 0.177
7 B c 32 75 0.114 0.260
8 B d 99 80 0.354 0.278
9 C a 6 31 0.0397 0.373
10 C b 8 5 0.0530 0.0602
11 C c 92 20 0.609 0.241
12 C d 45 27 0.298 0.325
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由reprex 包(v2.0.1)于 2021 年 12 月 20 日创建
数据表
library(data.table)
COLS <- c("January", "February")
COLS_RES <- paste0(COLS, "_perc")
setDT(data)[, (COLS_RES) := lapply(.SD, proportions), by = group, .SDcol = COLS][]
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