python 函数没有正确返回它们的值？

Question

我正在尝试学习 python，并且刚刚了解了条件语句，并且正在努力创建自己的函数。

您介意告诉我我做错了什么吗？我必须在最后编写复杂的打印语句来一一调用我的所有函数？

此外，任何风格提示也将不胜感激。

预先感谢您可以提供的任何信息。

import random

#VARIABLES
topChamps = ['Nasus', 'Garen', 'Nautilus']
botChamps = ['Draven', 'Caitlyn', 'Jhin']
midChamps = ['Lux', 'Veigar', 'Karthus']
supChamps = ['Sona', 'Tahm Kench', 'Alistar']
jgChamps = ['Amumu', 'Rammus', 'Malphite']
selectNum = 0
roleNum = 0
champArr = []
champ = "wrong"
role = str(input("what role did you get? "))

#function to make the role choice easier for computer to read
def roleChoose():
    if role == "top":
        roleNum = 1
    elif role == "bot":
        roleNum = 2
    elif role == "mid":
        roleNum = 3
    elif role == "sup":
        roleNum = 4
    elif role == "jg":
        roleNum = 5
    return roleNum


#function that determines what role list to use for champion choice
def arrayGrab(Num):
    if Num == 1:
       champArr = topChamps
    elif Num == 2:
        champArr = botChamps
    elif Num == 3:
        champArr = midChamps
    elif Num == 4:
        champArr = supChamps
    elif Num == 5:
        champArr = jgChamps
    return champArr
    print("made it to the end but you messed up")

#function that pulls a random name from champ list
def charSelect(arr):
    x = random.randrange(0,2)
    champ = arr[x]
    return champ


print(charSelect(arrayGrab(roleChoose())))

Answer 1

IIUC，你可以像这样取消打印：

role = roleChoose()
grab = arrayGrab(role)
char = charSelect(grab)

print(char)

在赋值的左侧使用您喜欢的任何变量名称。