假设如下表:
data <- data.table(dummy=1:10)
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我知道你可以做以下事情:
data[dummy < 5, c("test1", "test2") := list("Yes", 1)]
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和:
data[, test1 := fcase(dummy < 5, "Yes")]
data[, test2 := fcase(dummy < 5, 1)]
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我正在尝试将这些组合成一个,如下所示:
data[, c("test1", "test2") := fcase(dummy < 5, list("Yes", 1))]
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但它给了我以下错误:
Error in fcase(dummy < 5, list("Yes", 1)) :
Length of output value #2 must either be 1 or length of logical condition.
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我需要经过多个过滤器,所以使用fcase. 我总是可以对每个过滤器使用第一个解决方案,如下所示:
data[dummy < 5, c("test1", "test2") := list("Yes", 1)]
data[dummy > 7, c("test1", "test2") := list("No", 0)]
data[between(dummy, 5, 7), c("test1", "test2") := list("Maybe", NA)]
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但我想知道是否还有其他可能。还有一种解决方案,即使用test1和的每种组合创建一个表,并在执行for 仅test2之后将此表与数据表合并,如下所示:fcasetest1
tests <- data.table(test1 = c("Yes", "No", "Maybe"),
test2 = c(1, 0, NA))
data[, test1 := fcase(dummy < 5, "Yes",
dummy > 7, "No",
between(dummy, 5, 7), NA_character_)]
merge(data, tests, by = "test1", all.x = T, sort = F)
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但这对于大型且复杂的数据表来说似乎效率低下
和rbindlist:
data[, c("test1", "test2") := rbindlist(fcase(dummy < 5, .(.("Yes", 1)),
dummy > 7, .(.("No", 0)),
default = .(.("Maybe", NA))))]
data
#> dummy test1 test2
#> 1: 1 Yes 1
#> 2: 2 Yes 1
#> 3: 3 Yes 1
#> 4: 4 Yes 1
#> 5: 5 Maybe NA
#> 6: 6 Maybe NA
#> 7: 7 Maybe NA
#> 8: 8 No 0
#> 9: 9 No 0
#> 10: 10 No 0
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do.call可以让您将fcase条件放入一个列表中,并将值放入另一个嵌套列表列表中:
data[, c("test1", "test2") := rbindlist(do.call(fcase, rbind(.(dummy < 5, dummy <= 7, dummy > 7),
.(.(.("Yes", 1)), .(.("Maybe", NA)), .(.("No", 0))))))]
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或者用这个tests例子:
tests <- data.table(test1 = c("Yes", "Maybe", "No"),
test2 = c(1, NA, 0))
tests[, val := .(.(.(.SD))), by = 1:nrow(tests)]
data[, c("test1", "test2") := rbindlist(do.call(fcase, rbind(.(dummy < 5, dummy <= 7, dummy > 7), tests$val)))]
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