我正在制作匹配系统(玩家对玩家)我的目标是。我怎样才能确保键被附加到我的 div 中?
我之前已经用append制作了一个key。这是片段
const source = [{
entryID: 1,
entryName: 'player1',
weight: 1900,
},
{
entryID: 2,
entryName: 'player2',
weight: 1900,
},
{
entryID: 3,
entryName: 'player3',
weight: 1910,
},
{
entryID: 4,
entryName: 'player4',
weight: 1910,
},
{
entryID: 5,
entryName: 'player5',
weight: 1915,
},
{
entryID: 6,
entryName: 'player6',
weight: 1915,
},
{
entryID: 7,
entryName: 'player7',
weight: 1920,
},
{
entryID: 8,
entryName: 'player8',
weight: 1920,
},
{
entryID: 9,
entryName: 'player9',
weight: 1930,
},
{
entryID: 10,
entryName: 'player10',
weight: 1930,
},
]
const combine = (source) => {
return source.reduce((acc, curr) => {
if (acc[curr.weight]) {
const levelArr = acc[curr.weight];
const last = levelArr[levelArr.length - 1];
if (last.length === 2) {
levelArr.push([curr])
} else {
last.push(curr)
}
} else {
acc[curr.weight] = [
[curr]
];
}
return acc;
}, {})
};
var result = combine(source)
var html = ""
var keys = Object.keys(result) //if there are more than one keys i.e : 2..
for (var i = 0; i < keys.length; i++) {
result[keys[i]].forEach(function(val) {
val.forEach(function(value, index) {
var entryIDs = index == 0 ? "entryIDM[]" : "entryIDW[]"
var handlers = index == 0 ? "handlerM[]" : "handlerW[]"
var weights = index == 0 ? "weightM[]" : "weightW[]"
html += `<input type="text" name="${entryIDs}" value="${value.entryID}">
<input type="text" name="${handlers}" value="${value.entryName}">
<input type="text" name="${weights}" value="${value.weight}">
`
})
})
}
document.getElementById("result").innerHTML = html //add html to div
console.log(result);Run Code Online (Sandbox Code Playgroud)
<div id="result">
</div>Run Code Online (Sandbox Code Playgroud)
这些是我执行 newCombine 函数后的数据...现在我的目标是如何制作键并将这些结果附加为文本框?
当两个数据具有相同权重时,我提供的代码片段有效。它们组合成 1 个数组。实现我的目标,现在,我很难将其应用到我当前的函数中,该函数在 2 个数据的权重差异小于或大于等于 15 时起作用。请帮我。非常感谢。
html
<div id="appendhere"> </div>
Run Code Online (Sandbox Code Playgroud)
阿贾克斯
function newCombine(data, difference) {
let nonMatched = [...data]
const groups = {}
for (let i = 0; i < nonMatched.length - 1; i++) {
const first = nonMatched[i]
inner: for (let j = nonMatched.length - 1; j > i; j--) {
const second = nonMatched[j]
const delta = Math.abs(first.weight - second.weight)
if (delta <= difference && first.entryName !== second.entryName) {
const groupKey = `${first.weight}_${second.weight}`
groups[groupKey] = [first, second]
nonMatched = nonMatched.filter(
obj => obj.entryID != first.entryID && obj.entryID != second.entryID
)
i = -1
break inner
}
}
}
return { ...groups, ...nonMatched }
}
$(document).ready(function() {
var entry_list =$('#entry_list1').DataTable({
"ajax": {
"url": "<?php echo site_url('report/controlget')?>",
"type": "get",
success: function(data) {
const source = data;
const a = newCombine(source, 15);
console.log(a);
//How can i append my key here?
},
}
});
});
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我将在这里避免与控制台和 div 相关的内容,以确保该解决方案可以以任何方式重用。您可以对结果执行任何您想要的操作,包括将其添加到 div 或将其显示在控制台上。
我们需要使用标准对项目进行分组,根据该标准,权重差异小于给定值,例如。15.
让我们考虑一下当权重为 1900、1910 和 1920 时的示例。我们不能拥有权重组 (1900、1910 和 1920),因为 1920 - 1900 = 20 > 15。
我们可以有类似的权重组 (1900, 1910), (1920) 或 (1900), (1910, 1920)
const source = [{
entryID: 1,
entryName: 'player1',
weight: 1900,
},
{
entryID: 2,
entryName: 'player2',
weight: 1900,
},
{
entryID: 3,
entryName: 'player3',
weight: 1910,
},
{
entryID: 4,
entryName: 'player4',
weight: 1910,
},
{
entryID: 5,
entryName: 'player5',
weight: 1915,
},
{
entryID: 6,
entryName: 'player6',
weight: 1915,
},
{
entryID: 7,
entryName: 'player7',
weight: 1920,
},
{
entryID: 8,
entryName: 'player8',
weight: 1920,
},
{
entryID: 9,
entryName: 'player9',
weight: 1930,
},
{
entryID: 10,
entryName: 'player10',
weight: 1930,
},
];
let groups = [];
for (let item of source) {
let found = false;
for (let group of groups) {
if (!found) {
let isFit = true;
for (let element of group) {
if (Math.abs(element.weight - item.weight) > 15) isFit = false;
}
if (isFit) {
group.push(item);
found = true;
}
}
}
if (!found) groups.push([item]);
}
document.getElementById("foo").innerText = JSON.stringify(groups);Run Code Online (Sandbox Code Playgroud)
<div id="foo"></div>Run Code Online (Sandbox Code Playgroud)
我们循环元素并将每个元素迭代到第一个匹配的组中。如果没有一个组匹配,我们将创建一个新组。
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