我试图在Scala中找出正确的语法,将一组函数应用于对象.说我有一节课:
class MiTestClass {
def isValid() : Bool = {...}
def isGreen() : Bool= {...}
def isYellow() : Bool = {...}
}
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我val miTestObj = new MiTestClass现在创建一个新对象我想将一个方法的子集应用到我的对象中
val conditions:List[MiTestClass => Boolean] = List(_.isGreen, _.isYellow)
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并执行某些操作,例如检查所有属性是否成立
val result:Bool = resultOfApplyingFunctions.foldLeft(true)(and)
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获得此类功能的语法是什么?在Haskell中你会写出类似的东西
map (\f -> f miTestObj) conditions
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但我无法正确使用Scala语法
scala> val conditions: List[MiTestClass => Boolean] = List(_.isGreen, _.isYellow)
conditions: List[(MiTestClass) => Boolean] = List(<function1>, <function1>)
scala> val obj = new MiTestClass
obj: MiTestClass = MiTestClass@3dc049d
scala> conditions.forall(_(obj))
res1: Boolean = false
scala> conditions.forall(f => f(obj)) // slightly more verbose way
res2: Boolean = false
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conditions.map(f => f(miTestObj))
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要么
conditions map (_(miTestObj))
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