如何使用 vi 命令重新编号行？

Question

2,$我正在尝试使用 vim 命令对文件中的行重新编号，我知道cat -nnl 命令，我可以对行进行编号，但我没有得到预期的输出：

我试过这个 :2,$s/^\([^,]\)// | 2,$!cat -n

输入：

#,Name,Types,Total,HP,Attack,Weaknesses,Strength
493,Arceus,Normal,720,120,120,Fighting,strong
483,Dialga,Steel;Dragon,680,100,120,Fighting;Ground,strong
250,Ho-oh,Fire;Flying,680,106,130,Electric;Water;Rock,strong
.... moer 100 lines

预期输出：

#,Name,Types,Total,HP,Attack,Weaknesses,Strength
1,Arceus,Normal,720,120,120,Fighting,strong
2,Dialga,Steel;Dragon,680,100,120,Fighting;Ground,strong
3,Ho-oh,Fire;Flying,680,106,130,Electric;Water;Rock,strong
....

Answer 1

您可以使用\=,sub-replace-expression和line('.')来获取当前行号：

" The parenthesis around `line('.')-1` are not needed, but it seems clearer to me
:2,$s/^/\=(line('.')-1).','/

编辑：刚刚意识到您实际上正在替换第一列，所以您可能实际上想要

:2,$s/^\d\+/\=line('.')-1/