Javascript三元运算符

mat*_*ley 0 javascript

我正在为谷歌地图创建两个不同的图标.但是只显示一个图标.一个名为facility的下拉选择将允许一个基于值'8'的图标,所有其他值将创建另一个图标.

var marker = createMarker(latlng, name, address, city, state, zipcode, telephone, images, url, facility);


function createMarker(latlng, name, address, city, state, zipcode, telephone, images, url, facility) { 
  var html = "<div id='infodiv'>" + name + "<br/><h4>" + address + "<br/>" + city + ", " + state + " " + zipcode + "<br/>" + (formatPhone(telephone)) + "</h4><div class='infoimage'><img src='" + images + "'></div><div class='footer'><a href='http://" + url + "'>" + url + "</a></div></div>";
  var marker = new google.maps.Marker({
    icon: icon2,
    icon: (facility == 8) ? icon : icon, 
    map: map, 
    position: latlng 
  });
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这是图标:

var icon = new google.maps.MarkerImage("./images/plum_flag.png", 
new google.maps.Size(35, 52), new google.maps.Point(0, 0), 
new google.maps.Point(0, 52));
//callup the orange icon
var icon2 = new google.maps.MarkerImage("./images/orange_flag.png", 
new google.maps.Size(26, 39), new google.maps.Point(0, 0), 
new google.maps.Point(0, 39));
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显示的唯一图标是'var icon = new google.maps.MarkerImage("./ images/plum_flag.png",'无论选择选项是什么......

pim*_*vdb 5

(facility == 8) ? icon : icon,
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意思是:如果facility8,使用icon,否则使用icon.不是很有用,因为它总是使用icon.

相反,你可能想要:

(facility == 8) ? icon : icon2,
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你可能会感到困惑,icon指的icon: icon2是你设置的前一个.但是,两者都icon指的是完全相同的东西,所以你不会看到任何区别.

由于您icon使用三元运算符进行定义,icon:因此也可以省略第一个icon:定义(第二个定义无论如何都会覆盖它).