Mac*_*sso 5 pivot-table r dataframe dplyr tidyverse
我有一个汇总为数据透视表的数据框,我想添加一行,其中包含每个数字列的平均值,对于字符列,该行可以命名为“平均值”
示例数据框如下
dat <- c('2000-01-15','2003-01-15','2000-02-15',
'2003-02-15','2000-04-15','2002-04-15',
'2000-12-15','2002-12-15','2003-12-13', "2003-12-15",'2002-02-21','2002-01-25','2003-04-24')
df <- data.frame(date =as.Date(dat), id = c(1,2,3,4,5,6,7,8,9,10,11,12,13),
sales = c(134,211,2000,234,421,400,34,1233,1222,1034,8034,1234,2331))
df <- df %>%
mutate(year = format(date, "%Y"),
month = format(date, "%b")) %>% select(-date) %>%
group_by(year,month) %>%
summarise(revenue = sum(sales))
df2 <- df %>% pivot_wider(id_cols = year, names_from = month, values_from = revenue)
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从这里我想做
rbind(df2, summarise_all(df2, mean))
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然而,主要的复杂性在于如何仅返回数字列的平均值并返回非数字列的字符。
我想要的输出应该是
year Apr Dec Feb Jan
<chr> <dbl> <dbl> <dbl> <dbl>
1 2000 421 34 2000 134
2 2002 400 1233 8034 1234
3 2003 2331 2256 234 211
4 mean 1051. 1174. 3423. 526.
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我们可以adorn_totals在末尾添加一个总和行,然后除以总行数 - 1
library(dplyr)
library(janitor)
df2 %>%
adorn_totals(name = "mean") %>%
mutate(across(where(is.numeric),
~ replace(., n(), .[n()]/(n()-1)))) %>%
as_tibble
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-输出
# A tibble: 4 x 5
year Apr Dec Feb Jan
<chr> <dbl> <dbl> <dbl> <dbl>
1 2000 421 34 2000 134
2 2002 400 1233 8034 1234
3 2003 2331 2256 234 211
4 mean 1051. 1174. 3423. 526.
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或者另一种选择是使用summarisewith在末尾across连接 ( c()) 一个值mean
df2 %>%
ungroup %>%
summarise(year = c(year, 'mean'),
across(where(is.numeric), ~ c(., mean(.))))
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-输出
# A tibble: 4 x 5
year Apr Dec Feb Jan
<chr> <dbl> <dbl> <dbl> <dbl>
1 2000 421 34 2000 134
2 2002 400 1233 8034 1234
3 2003 2331 2256 234 211
4 mean 1051. 1174. 3423. 526.
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或者使用add_row来自tibble
library(tibble)
df2 %>%
ungroup %>%
add_row(year = 'mean', !!! colMeans(.[-1]))
# A tibble: 4 x 5
year Apr Dec Feb Jan
<chr> <dbl> <dbl> <dbl> <dbl>
1 2000 421 34 2000 134
2 2002 400 1233 8034 1234
3 2003 2331 2256 234 211
4 mean 1051. 1174. 3423. 526.
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