按字符和rowname合并数据帧

spo*_*234 -4 merge r dplyr tidyr

我有两个这样的数据框:

set.seed(1)
df1 <- data.frame(v1 = rnorm(7),
              v2 = c("a1", NA, "a2", "a3", "a5", "a6", "a9"))


> df1
           v1   v2
1  0.39956187   a1
2  0.33711756 <NA>
3 -0.19583763   a2
4  0.04880812   a3
5 -2.07266374   a5
6 -0.83824743   a6
7  1.31302096   a9


df2 <- data.frame(pc1 = rnorm(5),
                  pc2 = rnorm(5))
rownames(df2) <- c("a1", "a2", "a3", "a6", "a9")


> df2
           pc1         pc2
a1 -0.89865755 -0.32949632
a2 -0.05709327 -0.06923935
a3 -0.44229588  0.32089049
a6 -1.51754734 -0.34285758
a9  0.99955141 -0.62749542
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df1有一列v2包含与rownames匹配的字符值df2.但它也有NAs并且可能包含没有相应的rownames df2存在的字符.

我现在想要将这些数据框合并为一个,如下所示:

           v1   v2           pc1         pc2
1  0.39956187   a1   -0.89865755 -0.32949632
2  0.33711756   NA            NA          NA
3 -0.19583763   a2   -0.05709327 -0.06923935
4  0.04880812   a3   -0.44229588  0.32089049
5 -2.07266374   a5            NA          NA
6 -0.83824743   a6   -1.51754734 -0.34285758
7  1.31302096   a9    0.99955141 -0.62749542
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我怎样才能做到这一点.我更喜欢dplyr(tydiverse)解决方案.

akr*_*run 5

我们可以用来rownames_to_column从行名创建一个列,然后做一个left_join

library(tidyverse)
rownames_to_column(df2, "v2") %>%
                   left_join(df1, .)
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