javascript与unicode排序

Question

有很多例子可以通过某些属性(即'title')对一些JSON数组进行排序.我们正在使用比较函数,如下所示:

function sortComparer(a, b) {
        if (a.title == b.title)
            return 0;
        return a1 > b1 ? 1 : -1;
    }

问题是塞尔维亚拉丁字母顺序看起来像"A,B,C,Č,Ć,D,......"当使用上面的sortComparer时,我在"Č"或"Ć"之前得到D排序.知道如何对当前的文化语言进行排序吗？

Answer 1

如果系统中的语言环境设置正确,那么您可以使用localeCompare方法而不是大于运算符来比较字符串 - 此方法可识别语言环境.

function sortComparer(a,b){
    return a.title.localeCompare(b.title)
};

Answer 2

要使用自定义设置对数组进行排序，请执行以下操作：

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1. 创建一个具有自定义字母顺序的数组：

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   var alphabets = ["A", "B", "C", "\xc4\x8c", "\xc4\x86", "D","D\xc5\xbe","\xc4\x90","E","F","G","H","I","J","K","L","Lj","M","N","Nj","O","P","R","S", "\xc3\x9b\xc5\x92","T","U","V","Z","\xc5\xbd"];

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2. 创建测试数组列表：

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   var testArrray = ["B2","D6","A1","\xc4\x865","\xc4\x8c4","C3"];

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3. 创建排序函数名称：

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   function OrderFunc(){\n          testArrray.sort(function (a, b) {\n              return CharCompare(a, b, 0);\n          });\n      }\n

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4. 创建 CharCompare 函数（索引：在“AAAC”之前排序“AAAB”）：

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    function CharCompare(a, b, index) {\n  if (index == a.length || index == b.length)\n      return 0;\n  //toUpperCase: isn\'t case sensitive\n  var aChar = alphabets.indexOf(a.toUpperCase().charAt(index));\n  var bChar = alphabets.indexOf(b.toUpperCase().charAt(index));\n  if (aChar != bChar)\n      return aChar - bChar\n  else\n      return CharCompare(a,b,index+1)\n }\n

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5. 调用 OrderFunc 对 testArray 进行排序（结果将是：A1,B2,C3,\xc4\x8c4,\xc4\x865,D6）。

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在线测试

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祝你好运

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