Rau*_*osa 5 php dependency-injection symfony symfony-console
我一直在使用 symfony/console 来创建命令并像这样注册它们,一切正常:
垃圾箱/控制台:
#!/usr/bin/env php
<?php
require_once __DIR__ . '/../vendor/autoload.php';
use App\Commands\LocalitiesCommand;
use Symfony\Component\Console\Application;
$app = new Application();
$app->add(new LocalitiesCommand(new LocalitiesGenerator()));
$app->run();
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src/Commands/LocalitiesCommand.php:
<?php
declare(strict_types=1);
namespace App\Commands;
use App\LocalitiesGenerator;
use Symfony\Component\Console\Command\Command;
use Symfony\Component\Console\Input\InputInterface;
use Symfony\Component\Console\Output\OutputInterface;
final class LocalitiesCommand extends Command
{
protected static $defaultName = 'app:generate-localities';
public function __construct(private LocalitiesGenerator $localitiesGenerator)
{
parent::__construct();
}
protected function configure(): void
{
$this
->setDescription('Generate localities.json file')
->setHelp('No arguments needed.');
}
protected function execute(InputInterface $input, OutputInterface $output): int
{
$this->localitiesGenerator->generateJsonLocalities();
$output->writeln("File localities.json generated!");
return Command::SUCCESS;
}
}
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现在我想使用 symfony/dependency-injection 自动注入服务,我正在阅读文档并做了一些更改:
新垃圾箱/控制台:
#!/usr/bin/env php
<?php
require_once __DIR__ . '/../vendor/autoload.php';
use App\Commands\LocalitiesCommand;
use Symfony\Component\Console\Application;
use Symfony\Component\DependencyInjection\ContainerBuilder;
use Symfony\Component\DependencyInjection\Loader\YamlFileLoader;
use Symfony\Component\Config\FileLocator;
$container = new ContainerBuilder();
$loader = new YamlFileLoader($container, new FileLocator(__DIR__.'/src/config'));
$loader->load('services.yaml');
$container->compile();
$app = new Application();
$app->add(new LocalitiesCommand());
$app->run();
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配置/services.yaml:
services:
_defaults:
autowire: true
autoconfigure: true
public: false
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但当我实例化我的命令时,仍然要求我在构造函数中添加我的服务。为什么它不起作用?
yiv*_*ivi 10
首先,我们要澄清一个误解:
\n\n\n但当我实例化我的命令时,仍然要求我在构造函数中添加我的服务。为什么它不起作用?
\n
如果您致电new Foo(),那么您将不再获得自动连线 DI 权益。如果你想使用自动装配和自动依赖注入,你需要让 Symfony 为你工作。你打电话时new,您正在手动实例化对象,并且您需要自己处理 DI。
既然如此,你将如何做到这一点呢?
\n第一的,composer.json具有基本的依赖项和自动加载器声明:
完整的目录结构最终将如下所示:
\n<project_dir>\n\xe2\x94\x9c\xe2\x94\x80\xe2\x94\x80 composer.json \n\xe2\x94\x9c\xe2\x94\x80\xe2\x94\x80 app \n\xe2\x94\x9c\xe2\x94\x80\xe2\x94\x80 src/\n\xe2\x94\x82 \xe2\x94\x9c\xe2\x94\x80\xe2\x94\x80 ConsoleCommand/\n\xe2\x94\x82 \xe2\x94\x82 \xe2\x94\x94\xe2\x94\x80\xe2\x94\x80 FooCommand.php\n\xe2\x94\x82 \xe2\x94\x94\xe2\x94\x80\xe2\x94\x80 Text/\n\xe2\x94\x82 \xe2\x94\x94\xe2\x94\x80\xe2\x94\x80 Reverser.php\n\xe2\x94\x9c\xe2\x94\x80\xe2\x94\x80 config/\n\xe2\x94\x82 \xe2\x94\x9c\xe2\x94\x80\xe2\x94\x80 services.yaml\nRun Code Online (Sandbox Code Playgroud)\n现在,每个部分:
\n这composer.json包含所有依赖项和自动加载器的文件
{\n "require": {\n "symfony/dependency-injection": "^5.3",\n "symfony/console": "^5.3",\n "symfony/config": "^5.3",\n "symfony/yaml": "^5.3"\n },\n "autoload": {\n "psr-4": {\n "App\\\\": "src"\n }\n }\n}\nRun Code Online (Sandbox Code Playgroud)\n前端控制器脚本,运行应用程序的文件(app在我的例子中):
#!/usr/bin/env php\n<?php declare(strict_types=1);\n\nuse Symfony\\Component;\n\nrequire __DIR__ . \'/vendor/autoload.php\';\n\nclass App extends Component\\Console\\Application\n{\n\n public function __construct(iterable $commands)\n {\n $commands = $commands instanceof Traversable ? iterator_to_array($commands) : $commands;\n\n foreach ($commands as $command) {\n $this->add($command);\n }\n\n parent::__construct();\n }\n}\n\n$container = new Component\\DependencyInjection\\ContainerBuilder();\n$loader = new Component\\DependencyInjection\\Loader\\YamlFileLoader($container, new Component\\Config\\FileLocator(__DIR__ . \'/config\'));\n\n$loader->load(\'services.yaml\');\n$container->compile();\n\n$app = $container->get(App::class);\n$app->run();\nRun Code Online (Sandbox Code Playgroud)\n项目的服务容器配置:
\n# config/services.yaml\nservices:\n _defaults:\n autowire: true\n\n _instanceof:\n Symfony\\Component\\Console\\Command\\Command:\n tags: [ \'app.command\' ]\n\n App\\:\n resource: \'../src/*\'\n\n App:\n class: \\App\n public: true\n arguments:\n - !tagged_iterator app.command\nRun Code Online (Sandbox Code Playgroud)\n一FooCommand类:
<?php declare(strict_types=1);\n\n// src/ConsoleCommand/FooCommand.php\n\nnamespace App\\ConsoleCommand;\n\nuse App\\Text\\Reverser;\nuse Symfony\\Component\\Console;\n\nclass FooCommand extends Console\\Command\\Command\n{\n\n protected static $defaultName = \'foo\';\n\n public function __construct(private Reverser $reverser)\n {\n parent::__construct(self::$defaultName);\n }\n\n protected function execute(Console\\Input\\InputInterface $input, Console\\Output\\OutputInterface $output): int\n {\n $output->writeln(\'Foo was invoked\');\n $output->writeln($this->reverser->exec(\'the lazy fox\'));\n\n return self::SUCCESS;\n }\n}\nRun Code Online (Sandbox Code Playgroud)\n以上取决于App\\Text\\Reverser服务,DI组件会自动为我们注入:
<?php declare(strict_types=1);\n\nnamespace App\\Text;\n\nclass Reverser\n{\n\n public function exec(string $in): string\n {\n return \\strrev($in);\n }\n}\nRun Code Online (Sandbox Code Playgroud)\n安装并转储自动加载器后,通过执行php app(1) 我发现该foo命令可用 (2):\n
我可以执行php app foo,并且使用其注入的依赖项正确执行该命令:
一个独立的 Symfony 控制台应用程序,具有最小的依赖项和自动依赖项注入。
\n(这里是一个非常相似的示例的所有代码)。
\n