C#查找两个纬度/经度的中点

Question

我需要找到两个纬度/经度点之间的中点.

我试图将我绘制的两个位置之间的地图居中,并且需要找到该点.

我已经从我找到的其他示例中编写了这个函数,但似乎没有用.

    public static void midPoint(double lat1, double lon1, double lat2, double lon2, out double lat3_OUT, out double lon3_OUT)
    {
        //http:// stackoverflow.com/questions/4656802/midpoint-between-two-latitude-and-longitude
        double dLon = DistanceAlgorithm.Radians(lon2 - lon1);

        //convert to radians
        lat1 = DistanceAlgorithm.Radians(lat1);
        lat2 = DistanceAlgorithm.Radians(lat2);
        lon1 = DistanceAlgorithm.Radians(lon1);

        double Bx = Math.Cos(lat2) * Math.Cos(dLon);
        double By = Math.Cos(lat2) * Math.Sin(dLon);
        double lat3 = Math.Atan2(Math.Sin(lat1) + Math.Sin(lat2), Math.Sqrt((Math.Cos(lat1) + Bx) * (Math.Cos(lat1) + Bx) + By * By));
        double lon3 = lon1 + Math.Atan2(By, Math.Cos(lat1) + Bx);

        lat3_OUT = lat3;
        lon3_OUT = lon3;
    }

这是一个示例输出.

lat1  37.7977008
lat2  37.798392     
lon1  -122.1637914      
lon2  -122.161464       
lat3  0.65970036060147585   
lon3  -2.1321400763480485   

见Lat3和Lon3.

谢谢!

Answer 1

看来您的输出是正确的，除了它以弧度为单位并且您期望的是度数？您可能需要从弧度转换为度数才能满足预期的输出。

-(2.1321400763480485 radians) = -122.162628 degrees
0.65970036060147585 radians = 37.7980464 degrees

看起来您已经在使用 Jon Martin 和 IanDotKelly 提到的大圆算法。