mysql_num_rows的问题

Question

这是我的代码:

$sql1 = 'SELECT * FROM login WHERE age= "$age", town = "$town" and ID != "$id"';
$result1 = mysql_query($sql1);
$numResults1 = mysql_num_rows($result1);

我的变量很好,他们有数据.错误是这样的:

警告:mysql_num_rows():提供的参数不是.....中有效的MySQL结果资源

numResults有可能等于0但它仍然不应该导致这种情况.

它可能是导致它的第一行中的!=吗？

Answer 1

问题是你有一个错误的SQL查询:

$sql1 = 'SELECT * FROM login WHERE age= "$age", town = "$town" and ID != "$id"';

注意不当,后age = "$age"的在WHERE条款.它应该是这样的:

$sql1 = "SELECT * FROM login WHERE age= '$age' AND town = '$town' and ID != '$id'";