在对象数组中搜索多个值

Question

我有对象数组：

[
  {
    "caseNumber": 123,
    "patientName": "John Doe",
    "technician": "Jasmin Joe",
    "reader": "Jade Boe"
  },
  {
    "caseNumber": 123,
    "patientName": "John Doe",
    "technician": "Jasmin Joe",
    "reader": "Jade Boe"
  },
  {
    "caseNumber": 123,
    "patientName": "John Doe",
    "technician": "Jasmin Joe",
    "reader": "Jade Boe"
  }
]

我的顶部有一个搜索栏，想要从我提供的任何键中搜索任何匹配的字符串。例如：我想从 caseNumber、patentName 和 reader 中进行搜索，因此我将调用我的过滤器函数作为 filter(allCases, caseNumber, PatientName, reader) 我尝试使用 Angular Pipers，但它仅适用于前两个键。

我尝试了下面的代码：

this.activeCases = this.filterPipe.transform(
      activeCases,
      this.searchUser,
      this.isCurrentUserTech ? 'readerName' : 'techName',
      'patientFullName',
      'caseNumber'
    );

我的管道功能：

@Pipe({
  name: 'filter'
})
export class FilterPipe implements PipeTransform {
  transform(items: any[], value: string, label: string, optionalLabel?: string, optionalLabel2?: string, optionalValue?: string): any[] {
    if (!items) {
      return [];
    }
    if (!optionalValue && !value) {
      return items;
    }

    if ((value === '' || value == null) && (optionalValue === '' || optionalValue == null)) {
      return [];
    }

    if (optionalValue && optionalLabel) {
      this.filterByValue(value, items, label, optionalLabel, optionalValue);
    } else if (optionalLabel) {
      return items.filter(e => (e[optionalLabel] + ', ' + e[label]).toLowerCase().indexOf(value.toLowerCase()) > -1);
    } else if (optionalLabel && label && value) {
      return items.filter(item => {
        let object: any = { item1: optionalLabel, item2: label };
        if (optionalLabel2) {
          object = { item1: optionalLabel, item2: label, item3: optionalLabel2 };
        }
        for (const property in object) {
          if (item[object[property]] === null) {
            continue;
          }
          if (item[object[property]].toString().toLowerCase().includes(value.toLowerCase())) {
            return true;
          }
        }
        return false;
      });
    } else {
      return items.filter(e => {
        const tempValue = e[label] ? e[label].toLowerCase() : '';
        return tempValue.indexOf(value.toLowerCase()) > -1;
      });
    }
  }

  filterByValue(value, items, label, optionalLabel, optionalValue) {
    if (value) {
      return items.filter(e => {
        const firstLabel = e[label] ? e[label].toLowerCase() : '';
        const secondLabel = e[optionalLabel] ? e[optionalLabel].toLowerCase() : '';
        const firstValue = value ? value.toLowerCase() : value;
        const secondValue = optionalValue ? optionalValue.toLowerCase() : optionalValue;
        let firstCheck = false;
        let secondCheck = false;
        if (firstLabel && firstValue) {
          firstCheck = firstLabel.includes(firstValue);
        }
        if (secondLabel && secondValue) {
          secondCheck = secondLabel.includes(secondValue);
        }
        return firstCheck && secondCheck;
      });
    } else {
      return items.filter(e => {
        const tempValue = e[optionalLabel] ? e[optionalLabel].toLowerCase() : '';
        return tempValue.indexOf(optionalValue.toLowerCase()) > -1;
      });
    }
  }
}

我缺少什么？我也可以使用lodash

Answer 1

const data = [{
    caseNumber: 123,
    patientName: 'Adam',
    technician: 'Jasicca',
    reader: 'Potter',
  },
  {
    caseNumber: 456,
    patientName: 'John Doe',
    technician: 'Kevin',
    reader: 'Harry',
  },
  {
    caseNumber: 789,
    patientName: 'Ram',
    technician: 'Bob',
    reader: 'Jade Boe',
  },
];

const input = document.querySelector('input');
const log = document.getElementById('log');

function searchArray(e) {
  let filtered = [];
  const input = e.target.value.toLowerCase();
  if (input) {
    filtered = data.filter((el) => {
      return Object.values(el).some((val) =>
        String(val).toLowerCase().includes(input)
      );
    });

    log.textContent = JSON.stringify(filtered);
  }
}

<input placeholder="Enter some text" name="name" onkeyup="searchArray(event)" />
<p id="log"></p>