当我在海边2.9使用'jQuery ajax'时,为什么我的服务器端回调没有出现?

Ste*_*ble 2 ajax jquery seaside

我想在海边2.9做这样的事情

html button 
 onClick: (html jQuery ajax
  serialize: (html jQuery this);
  script: [:s | s << (s jQuery id: stratId) append: [html text: 'bing'. html break]]);
 callback: [2 inspect];
with: 'add option'.
Run Code Online (Sandbox Code Playgroud)

而且我希望我的div与stratId相加,但我的吱吱声图像中没有检查窗口?这样做的正确方法是什么?

Luk*_*gli 5

答案是在JQueryInstance的方法注释的第二部分>> #serializeThis:

"Serialize the receiving element. Note that this might not work for all form elements: (1) for check-boxes and multi-select lists Seaside internally depends on an additional hidden form element that is generated automatically, instead use #serializeThisWithHidden (2) submit-button callbacks are ignored, instead use a normal callback to trigger specific code evaluation."

而是将您的回调代码放入jQuery回调本身,即#script:block.