设置剪刀布获胜规则，无需大量 if 语句

Question

我当时正在做一个剪刀石头布挑战，当我需要设置一个决定获胜者的函数时，我觉得编写大量包含每个潜在情况的 if 语句根本不切实际。但在我进行了一次小搜索之后，我检查过的所有代码都使用了 if 语句。\xe2\x80\x99t 有没有更好的方法来做到这一点？

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我将分享下面的代码：

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 //after the user clickes on scissor or paper or rock mymove function runs.\nfunction mymove(choice) {\n     let humanchoice = choice.id \n    //a while loop that runs till the computer choice is not the same as the user choice\n    while (true){\n         let pcnum = Math.random();\n         console.log(pcnum);\n         let pcchoie = 'paper';\n\n        \n         if(pcnum <= 0.33){\n         pcchoie = "paper";\n      \n    } else if(pcnum <= 0.66){\n         pcchoie = "scissor"; \n    }else {\n         pcchoie = "rock"; \n       \n    }\n    console.log(pcchoie); \n\n    \n    if(humanchoice == pcchoie){ console.log ("lag");}\n    else if(humanchoice != pcchoie){ break;}\n}\n

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}

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现在我需要一种方法来设置规则，让计算机决定谁是赢家。

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Answer 1

您可以在对象中表示获胜者逻辑：

const beatenBy = {
  "scissor": "paper",
  "paper": "rock",
  "rock": "scissor"
};

function decideWinner(humanChoice, pcChoice) {
  if (humanChoice === pcChoice) {
    return "draw";
  }
  else if beatenBy[humanChoice] === pcChoice {
    return "human";
  }
  else {
    return "pc";
  }
}