在for循环中将shell变量传递给awk

Question

我正在编写一个脚本来打印与给定字符串匹配的单元格的列号和行号，然后将其输出到文本文件。各个awk命令在终端中运行良好，我已经解决了其他语法问题，但输出的 .txt 仍然为空。我想我在将 shell 变量传递给awk.

#!/bin/bash

echo Literal or regex string to find:
read string
echo File path to find string match in:
read filename

echo "Matches for $string were found in the following cells:" > results.txt

for string in filename
do
    awk -v awkvar="$string" -F"," '{for(i=1;i<=NF;i++){if ($i ~ /awkvar/){print i}}}' $filename >> results.txt | echo -e "\n" >> results.txt
    awk -v awkvar="$string" '/awkvar/{print NR}' $filename >> results.txt | echo -e "\n" >> results.txt
done

问题已解决

我已经将脚本重写如下：

#!/bin/bash

# Prompt for input: 1. enter file name or path that you want searched; 2. enter the literal or regex string
echo File name or path to find matches in:
read file
echo Literal or regex string to find:
read string

# Define variable and test if any matches are to be found; if not, notification is sent to terminal, but if matches exist, their row numbers (as summary rows) and individual column numbers will be output to a .txt file in the home directory. NB: you need to escape minus symbol with brackets, [-], so that it's not confused with an invalid grep option!
matchesFound=$(cat $file | grep -E -c "$string")
if [ $matchesFound -eq 0 ];
then
    echo "No matches exist."
else
    printf "Summary Row No: \n`awk -v awkvar="$string" '$0 ~ awkvar{print NR}' $file`" > results_for_$string.txt
    printf "\nInstance Column No: \n`awk -v awkvar="$string" -F"," '{for(i=1;i<=NF;i++){if ($i ~ awkvar){print i}}}' $file`" >> results_for_$string.txt
fi

Answer 1

您不能awk在正则表达式检查模式中使用变量，请尝试以下操作。您可以使用andindex函数awk来检查条件是否尝试/../。

awk -v awkvar="$string" -F"," '{for(i=1;i<=NF;i++){if ($i ~ awkvar){print i}}}' $filename >> results.txt | echo -e "\n" >> results.txt
awk -v awkvar="$string" 'index($0,awkvar){print NR}' $filename >> results.txt | echo -e "\n" >> results.txt

这个答案只处理awkOP 根据问题显示的代码，以修复它。