如何在PHP中对Mysql表进行分页

Question

如何在PHP中对Mysql表进行分页

我在mysql中有一个表.因为它有很多行,我想在页面中放置每10行,然后单击链接向我显示10行.有什么解决方案吗？

Answer 1

这真的很棒http://www.phpsimplicity.com/tips.php?id=1

它很简单!无需与大班一起工作!我很开心:D

<!DOCTYPE html>
<html lang="en">
    <head>
        <title>Paginate</title>
    </head>
    <body>
    <form method='get'>
        <?php
        $connection = Mysql_connect( 'server', 'user', 'pass' );
        if ( ! $connection ) {
            echo 'connection is invalid';
        } else {
            Mysql_select_db( 'DB', $connection );

        }
        //Check if the starting row variable was passed in the URL or not
        if ( ! isset( $_GET['startrow'] ) or ! is_numeric( $_GET['startrow'] ) ) {

            //We give the value of the starting row to 0 because nothing was found in URL
            $startrow = 0;

            //Otherwise we take the value from the URL
        } else {
            $startrow = (int) $_GET['startrow'];
        }
        //This part goes after the checking of the $_GET var
        $fetch = mysql_query( "SELECT * FROM sample LIMIT $startrow, 10" ) or
        die( mysql_error() );
        $num = Mysql_num_rows( $fetch );
        if ( $num > 0 ) {
            echo '
        <table border=2>';
            echo '
            <tr>
                <td>ID</td>
                <td>Drug</td>
                <td>quantity</td>
            </tr>
            ';
            for ( $i = 0; $i < $num; $i ++ ) {
                $row = mysql_fetch_row( $fetch );
                echo '
            <tr>';
                echo "
                <td>$row[0]</td>
                ";
                echo "
                <td>$row[1]</td>
                ";
                echo "
                <td>$row[2]</td>
                ";
                echo '
            </tr>
            ';
            }//for
            echo '
        </table>
        ';
        }

        //Now this is the link..
        echo '<a href="' . $_SERVER['PHP_SELF'] . '?startrow=' . ( $startrow + 10 ) . '">Next</a>';

        $prev = $startrow - 10;

        //only print a "Previous" link if a "Next" was clicked
        if ( $prev >= 0 ) {
            echo '<a href="' . $_SERVER['PHP_SELF'] . '?startrow=' . $prev . '">Previous</a>';
        }
        ?>
    </form>
    </body>
</html>

Run Code Online (Sandbox Code Playgroud)

顺便说一下rickyduck的链接也很好

归档时间：	14 年，10 月前
查看次数：	26512 次
最近记录：	6 年，11 月前