Matplotlib Colorbar 缺少 1 个必需的位置参数：“可映射”

Question

我想为下面的数据框创建一个散点图：

df_sample.head(10)

    duration  distance speed
0   26.299999   3.569   8.1
1   6.000000    0.739   7.4
2   25.700001   2.203   5.1
3   34.400002   2.876   5.0
4   3.000000    0.656   13.1
5   29.299999   3.704   7.6
6   10.200000   2.076   12.2
7   4.000000    0.774   11.6
8   9.200000    1.574   10.3
9   10.800000   0.782   4.3

用下面的代码就差不多完成了。我想根据速度向图中添加颜色条（黄色：最慢和蓝色：最快），最终我在fig.colorbar(ax=ax)最后一行出现错误。请指教：什么是mappable？

with plt.style.context('seaborn-ticks'):

    fig, ax = plt.subplots(figsize = (10, 6))

    ax.set_title('Relationship between Distance & Duration', fontdict={'fontsize': 18, 'fontweight': 'bold'}, loc='left', pad=20)
    ax.scatter(x=df_sample.duration.values, y=df_sample.distance.values, c=df_sample.speed.values, cmap=cm.YlGnBu)

    # remove top & right spines
    ax.spines['top'].set_visible(False)
    ax.spines['right'].set_visible(False)

    # equivalent to 'sns.despine(offset = 5)'
    ax.spines['left'].set_position(('outward', 5))
    ax.spines['left'].set_linewidth(1.2)
    ax.spines['bottom'].set_position(('outward', 5))
    ax.spines['bottom'].set_linewidth(1.2)
    
    # set ticks & ticklabels
    xloc = np.arange(0, 45, 5)
    ax.set_xticks(xloc)
    ax.set_xticklabels(labels=xloc, fontdict={'fontsize': 12})
    ax.set_xlabel('Minute(s)', fontdict={'fontsize': 14, 'fontweight': 'bold'})
    
    yloc = np.arange(6)
    ylab = [f"{int(num)}" for num in yloc]
    ax.set_yticks(yloc)
    ax.set_yticklabels(labels=ylab, fontdict={'fontsize': 12})
    ax.set_ylabel("Distance (KM)" , fontdict={'fontsize': 14, 'fontweight': 'bold'})
    
    fig.colorbar(ax=ax);

Answer 1

您可以将散点图分配给变量，例如：

sp=ax.scatter(x=df_sample.duration.values, y=df_sample.distance.values, c=df_sample.speed.values, cmap=cm.YlGnBu)

然后将其作为可映射对象传递给颜色栏：

fig.colorbar(sp)