你可以使用left outer join和测试B.ID is null.此示例将在SQL Server 2008中运行,但查询在此之前的版本中运行.
declare @TableA table (ID int)
declare @TableB table (ID int)
insert into @TableA values (1),(2),(3),(4),(5),(6),(7),(8),(9),(10)
insert into @TableB values (1),(2),(3),(4)
select A.*
from @TableA as A
left outer join @TableB as B
on A.ID = B.ID
where B.ID is null
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结果:
ID
--
5
6
7
8
9
10
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