将uint8_t数组转换为NSString

Question

如何影响uint8_t数组(见decryptedBuffer下文)NSString？

uint8_t *decryptedBuffer;

NSString *cle2=[NSString stringWithUTF8String:decryptedBuffer];

NSString *str2=[player.name AES256DecryptWithKey:cle2]; 
NSLog(str2);


free(plainBuffer);
free(cipherBuffer);
free(decryptedBuffer);

Answer 1

uint8_t *只是一个与之兼容的字节字符串char *,所以你应该能够将转换的指针传递给stringWithUTF8String,假设解密的字符串是UTF-8并且它是NULL终止的:

NSString *s = [NSString stringWithUTF8String:(char *)decryptedBuffer];

如果数据不是NULL终止,您可以使用:

NSString *s = [[[NSString alloc] initWithBytes:decryptedBuffer
                                 length:length_of_buffer
                                 encoding:NSUTF8StringEncoding] autorelease];