React Native 上的react-i18next 没有重载与此调用打字稿匹配

Nic*_*ita 4 internationalization typescript react-native react-i18next react-native-ui-kitten

我正在尝试使用 typescript 4.1.2 在我的 React Native 应用程序中配置react-i18next 11.8.2:

i18n.use(initReactI18next).init({
  resources: {
    en,
    es,
  },
  lng: 'es',
  fallbackLng: 'es',
  interpolation: {
    escapeValue: false,
  },
});
Run Code Online (Sandbox Code Playgroud)

有两个资源文件(en,es)。

但我在使用 useTranslation 挂钩的 TFunction 接口中遇到打字稿错误:

const {t, i18n} = useTranslation(['SelectLanguage']);]

<StyledLabel>{t('SelectLanguage:title')}</StyledLabel>
Run Code Online (Sandbox Code Playgroud)

错误:

No overload matches this call.
  Overload 1 of 2, '(props: Pick<Pick<TextProps & RefAttributes<Text>, "key" | "ref" | "style" | "onLayout" | "testID" | "nativeID" | "accessible" | "accessibilityActions" | ... 35 more ... | "dataDetectorType"> & Partial<...>, "key" | ... 42 more ... | "dataDetectorType"> & { ...; } & { ...; } & { ...; }): ReactElement<...>', gave the following error.
    Type 'TFunctionResult' is not assignable to type 'string | number | TextElement | ChildElement[] | (string & {}) | (string & ReactElement<any, string | ((props: any) => ReactElement<any, string | ... | (new (props: any) => Component<any, any, any>)> | null) | (new (props: any) => Component<...>)>) | ... 20 more ... | undefined'.
      Type 'null' is not assignable to type 'string | number | TextElement | ChildElement[] | (string & {}) | (string & ReactElement<any, string | ((props: any) => ReactElement<any, string | ... | (new (props: any) => Component<any, any, any>)> | null) | (new (props: any) => Component<...>)>) | ... 20 more ... | undefined'.
  Overload 2 of 2, '(props: StyledComponentPropsWithAs<typeof Text, any, {}, never>): ReactElement<StyledComponentPropsWithAs<typeof Text, any, {}, never>, string | ... 1 more ... | (new (props: any) => Component<...>)>', gave the following error.
    Type 'TFunctionResult' is not assignable to type 'string | number | TextElement | ChildElement[] | (string & {}) | (string & ReactElement<any, string | ((props: any) => ReactElement<any, string | ... | (new (props: any) => Component<any, any, any>)> | null) | (new (props: any) => Component<...>)>) | ... 20 more ... | undefined'.
      Type 'null' is not assignable to type 'string | number | TextElement | ChildElement[] | (string & {}) | (string & ReactElement<any, string | ((props: any) => ReactElement<any, string | ... | (new (props: any) => Component<any, any, any>)> | null) | (new (props: any) => Component<...>)>) | ... 20 more ... | undefined'.ts(2769)
text.component.d.ts(15, 5): The expected type comes from property 'children' which is declared here on type 'IntrinsicAttributes & Pick<Pick<TextProps & RefAttributes<Text>, "key" | "ref" | "style" | "onLayout" | "testID" | ... 38 more ... | "dataDetectorType"> & Partial<...>, "key" | ... 42 more ... | "dataDetectorType"> & { ...; } & { ...; } & { ...; }'
text.component.d.ts(15, 5): The expected type comes from property 'children' which is declared here on type 'IntrinsicAttributes & Pick<Pick<TextProps & RefAttributes<Text>, "key" | "ref" | "style" | "onLayout" | "testID" | ... 38 more ... | "dataDetectorType"> & Partial<...>, "key" | ... 42 more ... | "dataDetectorType"> & { ...; } & { ...; } & { ...; }'
Run Code Online (Sandbox Code Playgroud)

我可以通过解析 i18n 翻译的结果来解决这个错误,如下所示:

<StyledLabel>{t<string>('SelectLanguage:title')}</StyledLabel>
Run Code Online (Sandbox Code Playgroud)

您知道为什么会发生这种情况吗?我认为它可能是 StyledLabel 道具,它只是 @ui-kitten/components Text 的样式组件

import styled from 'styled-components/native';
import {Text} from '@ui-kitten/components';

export const StyledLabel = styled(Text)`
  margin-bottom: 5px;
`;
Run Code Online (Sandbox Code Playgroud)

UI Kitten 的 text.component:

export declare class Text extends React.Component<TextProps> {
    render(): React.ReactElement<RNTextProps>;
}
export {};
Run Code Online (Sandbox Code Playgroud)

Ran*_*all 11

在错误信息中,你可以找到问题所在。

类型“TFunctionResult”不可分配给类型“string |” 数量 | 文本元素 | 子元素[] | (字符串&{})| (字符串 & ReactElement<任意, 字符串

TFunctionResult只接受字符串

解决方案:您需要始终发送一个字符串并将其引用为字符串

<StyledLabel>{t<string>('SelectLanguage:title')}</StyledLabel>
Run Code Online (Sandbox Code Playgroud)

第二种解决方案

<StyledLabel>{`${t('SelectLanguage:title')}`}</StyledLabel>
Run Code Online (Sandbox Code Playgroud)

  • 这与函数接受什么无关。TFunctionResult 将返回一个字符串,但它的类型不正确,不是字符串的子类型。 (2认同)