使用MAX并返回具有最大列值的整行

Question

我是SQL的新手,并且正在努力为我的MAX情况找到一个可行的解决方案.

我目前有一个表格如下:

ID   Date         Version
001  2010-11-17   2
001  2010-12-01   3
002  2011-01-11   1
002  2011-05-05   2

我想要的结果很简单:

ID   Date        Version
001  2010-12-01  3
002  2011-05-05  2

我不能在日期使用MAX和GROUP BY,因为Date不明显.

Answer 1

你可以用row_number它,比如:

select  *
from    (
        select  row_number() OVER(partition by id order by version desc) as rn
        ,       *
        from    YourTable
        ) as SubQueryAlias
where   rn = 1

Answer 2

这应该做的工作:

SELECT     ID,
           Date,
           Version
FROM       YourTable
INNER JOIN 
(
    SELECT    ID,
              Max(Version)
    FROM      YourTable
    GROUP BY  ID
) AS x
ON         YourTable.ID = x.ID
AND        YourTable.Version = x.Version