Android BroadcastReceiver android.intent.action.BATTERY_CHANGED

Bea*_*ear 7 android power-management broadcastreceiver

我能够Intent.ACTION_BATTERY_CHANGED在我的活动中听取意图并且效果很好.我尝试在清单中定义接收器:

<receiver android:name="com.beargreaves.battery.BatteryReceiver"> 
    <intent-filter> 
        <action android:name="android.intent.action.BATTERY_CHANGED" />
    </intent-filter> 
</receiver>
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但它没有用,我在这里读了一篇文章,说它必须以编程方式定义.我想在服务中实现这一点,而不是在我的Activity中注册接收器,以便它不断监视.我已经成功实现了这一点,并且它有效,但我想检查一下我的工作,看看它是否是正确的方法.

我开始扩展BroadcastReceiver:

public class BatteryReceiver extends BroadcastReceiver{
    @Override
    public void onReceive(Context context, Intent intent) {
        Bundle bundle = intent.getExtras();

        if(null == bundle)
            return;

        boolean isPresent = intent.getBooleanExtra("present", false);
        String technology = intent.getStringExtra("technology");
        int plugged = intent.getIntExtra("plugged", -1);
        int scale = intent.getIntExtra("scale", -1);
        int health = intent.getIntExtra("health", 0);
        int status = intent.getIntExtra("status", 0);
        int rawlevel = intent.getIntExtra("level", -1);
        int level = 0;

        Log.d("Debug","Battery Receiver OnReceive");

        if(isPresent) {
            if (rawlevel >= 0 && scale > 0) {
                level = (rawlevel * 100) / scale;

                Log.d("Debug","BatterReceiver: " + level);

                Toast.makeText(context,"Battery Receiver: " + level + "\t" + status + "Raw: " + rawlevel,Toast.LENGTH_LONG).show();

                if(level <60) {
                    /*
                     * Only invoke the service when level below threshold
                     */
                    Intent i = new Intent(context, BatteryService.class);
                    i.putExtra("level", level);
                    context.startService(i);
                }
            }
        }
    }
}
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然后我使用服务首先注册接收器onCreate(),然后处理事件onStart().如果级别低于阈值,我的BroadcastReceiver将启动服务.

public class BatteryService extends Service {
    /*
     * First Call to onStart we don't want to do anything
     */
    boolean avoidFirst = false;
    private BroadcastReceiver receiver;

    @Override
    public IBinder onBind(Intent intent) {
        // TODO Auto-generated method stub
        return null;
    }

    @Override
    public void onCreate() {
        super.onCreate();

        IntentFilter filter = new IntentFilter(Intent.ACTION_BATTERY_CHANGED);
        receiver = new BatteryReceiver();
        registerReceiver(receiver, filter);
    }

    @Override
    public void onStart(Intent intent, int startId) {
        Log.d("Debug","Battery Service On Start");
        int level = intent.getIntExtra("level", -1);

        if(avoidFirst) {
            if(level != -1) {
                Log.d("Debug","Battery Alert Notifying..... " + level);
                SMSManager.sendSMS(BatteryService.this, "<number redacted>", "Battery Level Aleart: " + level);
                stopSelf();
            }
        } else {
            avoidFirst = true;
        }
    }

    @Override
    public void onDestroy() {
        // TODO Auto-generated method stub
        super.onDestroy();
        PreferenceUtil.updatePreference(BatteryService.this, "battery_monitor_on", false);
        unregisterReceiver(receiver);
    }
}
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这是正确的方法吗?是注册接收器onCreate(),然后在收到事件时启动服务.首先我尝试不使用服务但是我无法注册接收器,因为它无法在清单中实现.其次,当我尝试发送短信时抛出异常onReceive().我读过onReceive()不应该开始任何线程.

提前致谢

Dar*_*tle 2

是的,这是正确的做法。这与我对我的应用程序所做的非常相似,十多年来,我的应用程序一直在生产中运行良好(自 Android 早期以来),并且我没有看到您在这里遗漏或出错的任何内容。您是对的,您无法从清单中注册该广播;您确实需要以编程方式执行此操作。根据您共享的其余内容,在服务而不是活动中执行此操作显然是正确的。