如何在iphone中将字节数组转换为base64字符串？

Question

我在vb中有一段代码.我需要将字节数组转换为base 64字符串.以下是vb代码.

如果arrLicence.Count> 0则

LicenceBytes = CType(Array.CreateInstance(GetType(Byte),6),Byte())

        LicenceBytes(0) = Convert.ToByte(arrLicence(0).ToString(), 16)
        LicenceBytes(1) = Convert.ToByte(arrLicence(1).ToString(), 16)
        LicenceBytes(2) = Convert.ToByte(arrLicence(2).ToString(), 16) 
        LicenceBytes(3) = Convert.ToByte(arrLicence(3).ToString(), 16) 
        LicenceBytes(4) = Convert.ToByte(arrLicence(4).ToString(), 16)
        LicenceBytes(5) = Convert.ToByte(arrLicence(5).ToString(), 16)

        LicenceString = Convert.ToBase64String(LicenceBytes) '6 byteArray - passed by the user - Base64Encoded

我需要它在iphone中的等价物.我试过NSData和base64转换,但结果推迟.

我用这个链接进行转换. http://www.cocoadev.com/index.pl?BaseSixtyFour

我尝试使用创建单个字节memcpy然后创建一个数组,但没有成功.

我试过的内容如下:

NSData *d1 =[@"64" dataUsingEncoding:NSUTF16StringEncoding];
NSData *d2 = [@"37" dataUsingEncoding:NSUTF16StringEncoding];
NSData *d3 = [@"81" dataUsingEncoding:NSUTF16StringEncoding];
NSData *d4 = [@"d4" dataUsingEncoding:NSUTF16StringEncoding];

unsigned char *buffer = (unsigned char*)malloc(8);
buffer[0] =  [d1 bytes]  ;
buffer[1] =  [d2 bytes] ;
buffer[2] =  [d3 bytes] ;
buffer[3] =  [d4 bytes] ;

NSData *data = [NSData dataWithBytes:buffer length:4];

NSString *str = [self encodeBase64WithData:data];
free(buffer);

这会导致IJCgkA==.NET 中的代码返回ZDeB1A==

请注意,转换是arrLicence的前四个字节,输入是64,37,81,d4

Answer 1

//strBusiCode = @"64-37-81-d4-39-6d";
NSArray *tmp_arr = [strBusiCode componentsSeparatedByString:@"-"];
NSMutableData *commandToSend= [[NSMutableData alloc] init];
unsigned char whole_byte;
char byte_chars[3] = {'\0','\0','\0'};
int i;
for (i=0; i < [tmp_arr count]; i++) {
    byte_chars[0] = [[tmp_arr objectAtIndex:i] characterAtIndex:0];
    byte_chars[1] = [[tmp_arr objectAtIndex:i] characterAtIndex:1];
    whole_byte = strtol(byte_chars, NULL, 16);
    [commandToSend appendBytes:&whole_byte length:1]; 
}
return commandToSend;

然后将此 commandToSend 转换为 base64 数据。