Vod*_*nik 1 sql informix average count sql-null
这是一个示例表 CALLRECORD:
+--------+------------+
|callid | rating |
|1 | |
|2 | 5 |
|3 | |
|4 | 1 |
|5 | |
+--------+------------+
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输出总通话数、评级通话数、平均评级和未评级通话数没有问题:
select count(*) as total from callrecord;
select count(*) as rated, avg(rating) as average_rating from callrecord where rating is not null;
select count(*) as unrated from callrecord where rating is null;
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+--------+
|total |
|5 |
+--------+
+--------+------------+
|rated |average |
|2 |3 |
+--------+------------+
+--------+
|unrated |
|3 |
+--------+
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我正在寻找如何使用单个 SQL 请求将以上所有内容输出到一行:
+--------+--------+------------+---------+
|total |rated |average |unrated |
|5 |2 |3 |3 |
+--------+--------+------------+---------|
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db<>在这里摆弄
大多数聚合函数会忽略null值,因此您想要的比您想象的更简单:
select
count(*) total, -- total number of rows
count(rating) as rated, -- count of non-null ratings
avg(rating) average, -- avg ignore `null`
count(*) - count(rating) unrated -- count of null ratings
from mytable
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