the*_*eve 6 django-views django-class-based-views
我有两个模型,城市和州,国家是City的ForeignKey关系.我的CityDetailView网址构造如下:
r'^state/(?P<state>[-\w]+)/city/(?P<slug>[-\w]+)/$'
Run Code Online (Sandbox Code Playgroud)
我上面的url调用的CityDetailView是:
class CityDetailView(DetailView):
model = City
context_object_name = 'city'
template_name = 'location/city_detail.html'
def get_queryset(self):
state = get_object_or_404(State, slug__iexact=self.kwargs['state'])
return City.objects.filter(state=state)
def get_context_data(self, **kwargs):
context = super(CityDetailView, self).get_context_data(**kwargs)
city = City.objects.get(slug__iexact=self.kwargs['slug'])
context['guide_list'] = Guide.objects.filter(location=city).annotate(Count('review'), Avg('review__rating'))
return context
Run Code Online (Sandbox Code Playgroud)
我的城市模型为每个城市都有唯一的名称.如果我尝试访问一个发生在两个州的城市,我会收到一个错误,即get()返回了多个城市.我试图覆盖get_queryset()方法只过滤掉单个状态的城市模型,但它似乎没有工作,这是奇怪的,因为我的CityListView相似,但工作正常.任何关于我失踪的想法都会受到赞赏.
小智 10
您需要覆盖的方法get_object中的DetailView做到这一点.
这样的事情应该做:
class CityDetailView(DetailView):
model = City
context_object_name = 'city'
template_name = 'location/city_detail.html'
def get_object(self):
state = get_object_or_404(State, slug__iexact=self.kwargs['state'])
return self.model.objects.filter(state=state)
def get_context_data(self, **kwargs):
context = super(CityDetailView, self).get_context_data(**kwargs)
cities = self.object
context['guide_list'] = Guide.objects.filter(location=cities).annotate(Count('review'), Avg('review__rating'))
return context
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
18210 次 |
| 最近记录: |