如何使用jQuery进入多维数组？奇怪的行为

Question

如果有人能解释我为什么警报器不返回数组但是空？

var response = new Array();
response[0] = new Array();
response[1] = new Array(); 
response[2] = new Array();  

response[0]["Id"] = 1;
response[0]["StreetAddress"] = 'xxx';
response[0]["Place"] = 'yyy';

response[1]["Id"] = 2;
response[1]["StreetAddress"] = 'xxx';
response[1]["Place"] = 'yyy';

response[2]["Id"] = 3;
response[2]["StreetAddress"] = 'xxx';
response[2]["Place"] = 'yyy';

$.each(response , function(key1, value1) {
    alert(value1);
});

实际上,我将从web服务中获得这种数组,我需要循环到这个数组中来检索数据.

但我不明白为什么循环不能正常工作.

先谢谢你们.

Answer 1

这不是一个多维数组,而是一个无效的代码.Arrays和Objects(哈希)是不同的东西,不像PHP那样.

所以在顶部你应该写下面的内容:

var response = new Array();
response[0] = new Object();
response[1] = {}; // it's the same
response[2] = new Object();

你可以像你一样迭代它:

$.each(response , function( index, obj ) {
    $.each(obj, function( key, value ) {
        console.log(key);
        console.log(value);
    });
});

Answer 2

如果你尝试:console.log(响应)...你会看到数组是空的,似乎数组不是很好.

为什么不使用JSON格式呢？

var response = [{
    "Id":"1",
    "StreetAddress": "xxx",
    "Place":"yyy"
},
{
    "Id":"2",
    "StreetAddress": "xxx2",
    "Place":"yyy2"
},
{
    "Id":"3",
    "StreetAddress": "xxx3",
    "Place":"yyy3"
}
]
console.log(response);
//you'll get an object: [Object { Id="1", StreetAddress="xxx", Place="yyy"}, Object { Id="2", StreetAddress="xxx2", Place="yyy2"}, Object { Id="3", StreetAddress="xxx3", Place="yyy3"}]
//iterate over
for(var x=0; x < response.length; x++){
    console.log("ID: " + response[x].Id + " StreetAddress: " + response[x].StreetAddress + " Place: " + response[x].Place);
}

Answer 3

你不应该在 Javascript 中使用这样的数组。数组是按数字索引的。如果你写

response[1]["Id"] = 2; 

您正在向 response[1] 数组添加一个属性

编辑-我更好地阅读了你的评论。它指出：

//仅供参考：输出是一个键值对数组（例如response[0].Id），键为：

所以你有一个对象数组。

这映射了您将收到的数据。

var response = new Array;
response[0] = new Object();
response[1] = new Object(); 
response[2] = new Object();  

response[0]["Id"] = 1;
response[0]["StreetAddress"] = 'xxx';
response[0]["Place"] = 'yyy';

response[1]["Id"] = 2;
response[1]["StreetAddress"] = 'xxx';
response[1]["Place"] = 'yyy';

response[2]["Id"] = 3;
response[2]["StreetAddress"] = 'xxx';
response[2]["Place"] = 'yyy';

你可以像这样访问它们：

jQuery.each(response, function(key, value){
         for (key2 in value[key]){
            if (value[key].hasOwnProperty(key2)){
            alert(mine[key2])
            }
         }
     });