lin*_*per 7 python python-3.x python-asyncio python-multiprocessing
如何终止loop.run_in_executor与ProcessPoolExecutor优雅?启动程序后不久,发送 SIGINT (ctrl + c)。
def blocking_task():
sleep(3)
async def main():
exe = concurrent.futures.ProcessPoolExecutor(max_workers=4)
loop = asyncio.get_event_loop()
tasks = [loop.run_in_executor(exe, blocking_task) for i in range(3)]
await asyncio.gather(*tasks)
if __name__ == "__main__":
try:
asyncio.run(main())
except KeyboardInterrupt:
print('ctrl + c')
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随着max_workers比的任务,一切正常的数量等于或更少。但是如果max_workers更大,上面代码的输出如下:
Process ForkProcess-4:
Traceback (most recent call last):
File "/usr/lib/python3.8/multiprocessing/process.py", line 315, in _bootstrap
self.run()
File "/usr/lib/python3.8/multiprocessing/process.py", line 108, in run
self._target(*self._args, **self._kwargs)
File "/usr/lib/python3.8/concurrent/futures/process.py", line 233, in _process_worker
call_item = call_queue.get(block=True)
File "/usr/lib/python3.8/multiprocessing/queues.py", line 97, in get
res = self._recv_bytes()
File "/usr/lib/python3.8/multiprocessing/connection.py", line 216, in recv_bytes
buf = self._recv_bytes(maxlength)
File "/usr/lib/python3.8/multiprocessing/connection.py", line 414, in _recv_bytes
buf = self._recv(4)
File "/usr/lib/python3.8/multiprocessing/connection.py", line 379, in _recv
chunk = read(handle, remaining)
KeyboardInterrupt
ctrl + c
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我想只捕获一次异常(KeyboardInterrupt)并忽略或静音进程池中的其他异常,但是如何?
更新额外信用:
您可以使用initializer 参数的ProcessPoolExecutor安装一个处理程序SIGINT中的每个过程。
更新:在 Unix 上,当进程被创建时,它成为其父进程组的成员。如果您正在生成SIGINTwith Ctrl+C,则信号将被发送到整个进程组。
import asyncio
import concurrent.futures
import os
import signal
import sys
from time import sleep
def handler(signum, frame):
print('SIGINT for PID=', os.getpid())
sys.exit(0)
def init():
signal.signal(signal.SIGINT, handler)
def blocking_task():
sleep(15)
async def main():
exe = concurrent.futures.ProcessPoolExecutor(max_workers=5, initializer=init)
loop = asyncio.get_event_loop()
tasks = [loop.run_in_executor(exe, blocking_task) for i in range(2)]
await asyncio.gather(*tasks)
if __name__ == "__main__":
try:
asyncio.run(main())
except KeyboardInterrupt:
print('ctrl + c')
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Ctrl-C 开始后不久:
^CSIGINT for PID= 59942
SIGINT for PID= 59943
SIGINT for PID= 59941
SIGINT for PID= 59945
SIGINT for PID= 59944
ctrl + c
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