Ste*_*lin 3 typescript reactjs typescript-generics storybook
如何编写泛型,以便结果采用提供给泛型的另一种类型的参数?
这是我的示例代码。
import { Story } from '@storybook/react/types-6-0';
type TKeyAny = {
[key: string]: string; // | 'other args values here...';
};
// this fails
export const bindargs = <A extends TKeyAny, T extends Story<A>>(args: A, Template: T): T => {
const Comp = Template.bind({});
Comp.args = args;
return Comp;
};
export default bindargs;
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这可以工作,但它并不特定于传递给它的参数,这就是为什么我想要一个通用的:
// This works but I'd like this instead to be in a generic
// export const bindargs = (args: TKeyAny, Template: Story<TKeyAny>): Story<TKeyAny> => {
// const Comp = Template.bind({});
// Comp.args = args;
// return Comp;
// };
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我们在 Storybook 中使用这样的泛型:
也许你可以做类似的事情
import React from 'react'
import { Meta, Story } from '@storybook/react/types-6-0'
import SelectDropdown, { ISelectDropdownProps, SelectOption } from './SelectDropdown'
export default {
title: 'Shared/Components/SelectDropdown',
component: SelectDropdown,
argTypes: {
options: {
control: {
type: 'object',
},
},
(...)
} as Meta
const Template = <T extends {}>(): Story<ISelectDropdownProps<T>> => args => (
<div
style={{
width: '300px',
}}
>
<SelectDropdown<T> {...args} />
</div>
)
export const Normal = Template<number>().bind({})
Normal.args = {
options: createOptions(5),
}
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