如何在一个请求中从 Binance API 获取所有（或多个）对的历史 klines？

Question

我有一个交易多对（30-40）的交易机器人。它使用之前的 5m 蜡烛作为价格输入。因此，我一一获得所有对的 5m 历史记录。目前，完整的周期大约需要 10 分钟，因此 500 万支蜡烛每 10 米更新一次，这是不好的。

关于如何加快速度的任何想法？

Answer 1

我认为最适合您的选择是 websocket 连接。您不能每次接收一次 kline 数据，例如。5 分钟，但您可以收到蜡烛的每一个变化，就像您在图表中看到的那样。Binance API 仅提供此功能，但结合 websocket 连接，它会非常快，而不是 10 分钟。

收到数据后，您只需指定蜡烛关闭的时间，您可以从 json 数据（'t' 和 'T'）中的时间戳来完成。[文档在这里]

您必须安装 websockets 库。

pip install websockets

这是一些示例代码，它是如何工作的。

import asyncio
import websockets


async def candle_stick_data():
    url = "wss://stream.binance.com:9443/ws/" #steam address
    first_pair = 'bnbbtc@kline_1m' #first pair
    async with websockets.connect(url+first_pair) as sock:
        pairs = '{"method": "SUBSCRIBE", "params": ["xrpbtc@kline_1m","ethbtc@kline_1m" ],  "id": 1}' #other pairs

        await sock.send(pairs)
        print(f"> {pairs}")
        while True:
            resp = await sock.recv()
            print(f"< {resp}")

asyncio.get_event_loop().run_until_complete(candle_stick_data())

输出：

< {"e":"kline","E":1599828802835,"s":"XRPBTC","k":{"t":1599828780000,"T":1599828839999,"s":"XRPBTC","i":"1m","f":76140140,"L":76140145,"o":"0.00002346","c":"0.00002346","h":"0.00002346","l":"0.00002345","v":"700.00000000","n":6,"x":false,"q":"0.01641578","V":"78.00000000","Q":"0.00182988","B":"0"}}
< {"e":"kline","E":1599828804297,"s":"BNBBTC","k":{"t":1599828780000,"T":1599828839999,"s":"BNBBTC","i":"1m","f":87599856,"L":87599935,"o":"0.00229400","c":"0.00229610","h":"0.00229710","l":"0.00229400","v":"417.88000000","n":80,"x":false,"q":"0.95933156","V":"406.63000000","Q":"0.93351653","B":"0"}}
< {"e":"kline","E":1599828804853,"s":"ETHBTC","k":{"t":1599828780000,"T":1599828839999,"s":"ETHBTC","i":"1m","f":193235180,"L":193235214,"o":"0.03551300","c":"0.03551700","h":"0.03551800","l":"0.03551300","v":"21.52300000","n":35,"x":false,"q":"0.76437246","V":"11.53400000","Q":"0.40962829","B":"0"}}
< {"e":"kline","E":1599828806303,"s":"BNBBTC","k":{"t":1599828780000,"T":1599828839999,"s":"BNBBTC","i":"1m","f":87599856,"L":87599938,"o":"0.00229400","c":"0.00229620","h":"0.00229710","l":"0.00229400","v":"420.34000000","n":83,"x":false,"q":"0.96497998","V":"406.63000000","Q":"0.93351653","B":"0"}}