在 django 项目中出现 typeError 错误

Question

我为我的新项目创建了一个虚拟环境，安装了 django 并启动了新项目。但是，每当我使用 manage.py 运行一行代码时，都会出现这个长错误。

PS D:\My stuff\Website development\Isow website\isow> python manage.py makemigrations
No changes detected
Traceback (most recent call last):
  File "manage.py", line 22, in <module>
    main()
  File "manage.py", line 18, in main
    execute_from_command_line(sys.argv)
  File "C:\Users\rahma\AppData\Local\Programs\Python\Python37\lib\site-packages\django\core\management\__init__.py", line 381, in execute_from_command_line
    utility.execute()
  File "C:\Users\rahma\AppData\Local\Programs\Python\Python37\lib\site-packages\django\core\management\__init__.py", line 375, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "C:\Users\rahma\AppData\Local\Programs\Python\Python37\lib\site-packages\django\core\management\base.py", line 336, in run_from_argv
    connections.close_all()
  File "C:\Users\rahma\AppData\Local\Programs\Python\Python37\lib\site-packages\django\db\utils.py", line 224, in close_all
    connection.close()
  File "C:\Users\rahma\AppData\Local\Programs\Python\Python37\lib\site-packages\django\db\backends\sqlite3\base.py", line 248, in close
    if not self.is_in_memory_db():
  File "C:\Users\rahma\AppData\Local\Programs\Python\Python37\lib\site-packages\django\db\backends\sqlite3\base.py", line 367, in is_in_memory_db
    return self.creation.is_in_memory_db(self.settings_dict['NAME'])
  File "C:\Users\rahma\AppData\Local\Programs\Python\Python37\lib\site-packages\django\db\backends\sqlite3\creation.py", line 12, in is_in_memory_db
    return database_name == ':memory:' or 'mode=memory' in database_name
TypeError: argument of type 'WindowsPath' is not iterable

数据库条目：

DATABASES = {
    'default': {
        'ENGINE': 'django.db.backends.sqlite3',
        'NAME': BASE_DIR / 'db.sqlite3',
    }
}

Answer 1

似乎 NAME 正在被转换为 pathlib.Path ( WindowsPath ) 对象而不是字符串，然后不能以与os.path期望字符串相同的方式在 Django 中使用（不是 100% 确定，因为没有深入调查）

所以用字符串转换是合适的

'NAME': str(os.path.join(BASE_DIR, "db.sqlite3"))