emi*_*ore 1 sql group-by concatenation string-concatenation google-bigquery
我正在使用 Google BigQuery & 我有一个如下所示的查询:
SELECT
prod.abc
uniqueid,
variable2,
cust.variable1,
purch.variable2,
from mydata.order
left join
UNNEST(purchases) as purch,
UNNEST(codes_abs) as cod, UNNEST(cod.try_products) as prod
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当我这样做时,会产生一个如下所示的表:
|prod.abc| uniqueid | variable2 | ...|
|APP123 | customer1| value | ...|
|BLU155 | customer1| value | ...|
|TRI134 | customer1| value | ...|
|LO123 | customer2| value | ...|
|ZU9274 | customer2| value | ...|
|TO134 | customer3| value | ...|
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我想做的是将“prod.abc”列中的值连接起来,按“uniqueid”对它们进行分组,并用“,”分隔它们。然而,我在网上找到了许多解决方案,因为我在查询中取消了其他变量的嵌套,所以我找到的解决方案似乎都不适合我的情况。这些值不需要以任何方式排序。基本上,我想要的结果是:
|prod.abc | uniqueid | variable2 | ...|
|APP123, BLU155, TRI134 | customer1| value | ...|
|LO123, ZU9274 | customer2| value | ...|
|TO134 | customer3| value | ...|
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获得一个像这样的保留重复项的表也可以,因为我可以稍后删除它们:
|prod.abc | uniqueid | variable2 | ...|
|APP123, BLU155, TRI134 | customer1| value | ...|
|APP123, BLU155, TRI134 | customer1| value | ...|
|APP123, BLU155, TRI134 | customer1| value | ...|
|LO123, ZU9274 | customer2| value | ...|
|LO123, ZU9274 | customer2| value | ...|
|TO134 | customer3| value | ...|
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任何帮助深表感谢。谢谢你!
分别取消嵌套:聚合有效吗?
SELECT STRING_AGG(item.abc, ',')
uniqueid, variable2, cust.variable1, purch.variable2
FROM mydata.order LEFT JOIN
UNNEST(purchases) as purch
ON true LEFT JOIN
UNNEST(codes_abs) as cod
ON true LEFT JOIN
UNNEST(cod.try_items) as item
ON true
GROUP BY uniqueid, variable2, cust.variable1, purch.variable2;
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