Zac*_*urn 5 c++ c++-concepts c++20
我试图理解如何声明一个需要特定运算符重载的概念。假设我有以下函数,它采用任意类型的向量并将其打印到std::cout:
template<typename printable>
void print_vector(const std::vector<printable>& vec)
{
std::cout << '{';
for (const printable &item : vec) {
std::cout << item << ',';
}
std::cout << '}';
}
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如果该类型printable具有重载<<运算符,则此代码将正常工作,但如果没有,则它会因非常无用的编译器错误而失败。我觉得我应该能够以某种方式声明一个需要<<定义了有效运算符的类型的概念,并在函数声明中使用该概念,以便我可以获得更有用的编译器错误,但我一直无法弄清楚如何去做。
template <class T>
concept Printable = requires(std::ostream& os, T a)
{
os << a;
};
template<Printable T>
void print_vector(const std::vector<T>& vec) {
std::cout << '{';
for (const auto &item : vec) {
std::cout << item << ',';
}
std::cout << '}';
}
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如果您愿意,还可以使其更通用地操作basic_ostream.
这是铛错误消息:
Run Code Online (Sandbox Code Playgroud)<source>:30:5: error: no matching function for call to 'print_vector' print_vector(x); ^~~~~~~~~~~~ <source>:19:6: note: candidate template ignored: constraints not satisfied [with T = X] void print_vector(std::vector<T> vec) { ^ <source>:18:10: note: because 'X' does not satisfy 'Printable' template<Printable T> ^ <source>:10:9: note: because 'os << a' would be invalid: invalid operands to binary expression ('std::ostream' (aka 'basic_ostream<char>') and 'X') os << a; ^
和 gcc:
Run Code Online (Sandbox Code Playgroud)<source>: In function 'auto test()': <source>:30:19: error: use of function 'void print_vector(std::vector<T>) [with T = X]' with unsatisfied constraints 30 | print_vector(x); | ^ <source>:19:6: note: declared here 19 | void print_vector(std::vector<T> vec) { | ^~~~~~~~~~~~ <source>:19:6: note: constraints not satisfied <source>: In instantiation of 'void print_vector(std::vector<T>) [with T = X]': <source>:30:19: required from here <source>:8:9: required for the satisfaction of 'Printable<T>' [with T = X] <source>:8:21: in requirements with 'std::ostream& os', 'T a' [with T = X] <source>:10:9: note: the required expression '(os << a)' is invalid 10 | os << a; | ~~~^~~~ cc1plus: note: set '-fconcepts-diagnostics-depth=' to at least 2 for more detail