怎么做:"今天和今天之间7"？

Question

我需要找到当天创建的帐户,过去7天.

为了找到我今天的结果,它可行,我这样做:

SELECT * FROM `account` where DATE(created_at) = DATE(NOW())

但我不知道如何做到最后7天的帐户.

我试过这样的事,但没有成功:

SELECT * FROM `account` where DATE(created_at) BETWEEN DATE(NOW()) AND DATE(NOW()-7)

你有个主意吗？

Answer 1

尝试:

BETWEEN (NOW() - INTERVAL 7 DAY) AND NOW()

Answer 2

在mysql中:

SELECT * FROM `account` 
WHERE DATE(created_at) > (NOW() - INTERVAL 7 DAY)