Geo*_*Geo 4 python language-features decorator
如果我有以下功能:
def intercept(func):
# do something here
@intercept(arg1=20)
def whatever(arg1,arg2):
# do something here
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我想拦截仅在arg1为20时启动.我希望能够将命名参数传递给函数.我怎么能做到这一点?
这是一个小代码示例:
def intercept(func):
def intercepting_func(*args,**kargs):
print "whatever"
return func(*args,**kargs)
return intercepting_func
@intercept(a="g")
def test(a,b):
print "test with %s %s" %(a,b)
test("g","d")
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抛出以下异常TypeError:intercept()得到一个意外的关键字参数'a'
Joh*_*uhy 15
记住这一点
@foo
def bar():
pass
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相当于:
def bar():
pass
bar = foo(bar)
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所以,如果你这样做:
@foo(x=3)
def bar():
pass
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这相当于:
def bar():
pass
bar = foo(x=3)(bar)
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所以你的装饰师需要看起来像这样:
def foo(x=1):
def wrap(f):
def f_foo(*args, **kw):
# do something to f
return f(*args, **kw)
return f_foo
return wrap
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换句话说,def wrap(f)它实际上是装饰器,foo(x=3)是一个返回装饰器的函数调用.
Mar*_*rot 11
from functools import wraps
def intercept(target,**trigger):
def decorator(func):
names = getattr(func,'_names',None)
if names is None:
code = func.func_code
names = code.co_varnames[:code.co_argcount]
@wraps(func)
def decorated(*args,**kwargs):
all_args = kwargs.copy()
for n,v in zip(names,args):
all_args[n] = v
for k,v in trigger.iteritems():
if k in all_args and all_args[k] != v:
break
else:
return target(all_args)
return func(*args,**kwargs)
decorated._names = names
return decorated
return decorator
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例:
def interceptor1(kwargs):
print 'Intercepted by #1!'
def interceptor2(kwargs):
print 'Intercepted by #2!'
def interceptor3(kwargs):
print 'Intercepted by #3!'
@intercept(interceptor1,arg1=20,arg2=5) # if arg1 == 20 and arg2 == 5
@intercept(interceptor2,arg1=20) # elif arg1 == 20
@intercept(interceptor3,arg2=5) # elif arg2 == 5
def foo(arg1,arg2):
return arg1+arg2
>>> foo(3,4)
7
>>> foo(20,4)
Intercepted by #2!
>>> foo(3,5)
Intercepted by #3!
>>> foo(20,5)
Intercepted by #1!
>>>
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functools.wraps做维基上的"简单装饰"; 更新__doc__,__name__以及装饰器的其他属性.
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