Java Iterator在C++中的等价物？(带代码)

Question

大家好.一位朋友为我编写了一些Java代码,我很容易将其转换为C++,但我对C++中的Java迭代器的等价物非常好奇.这是代码,我很可能希望将数据返回到向量中.任何帮助表示赞赏

public class RLEIterator
extends RegionIterator
{
    public int reg = 0;
    public int mode = 0;
    public int skip = 0;
        // mode is the number of IDs that are valid still (count down)
        // skip is used after we run out of mode IDs, and move forward
        //   The goal is, to always have a valid 'hasNext' state, after
        // an ID is read via 'next'. Thus, the initial search, and then
        // the reading forward if mode == 0, after the ID is found.
    public int i;

    public RLEIterator()
    {
        // Need to set up the skip of an initial part, so we can
        // correctly handle there not being anything, despite there
        // being data encoded.

        int comp;
        i = 0;

        while ((mode == 0) && (i<nearRLE.length))
        {
            // set up the next code
            comp = ((int)nearRLE[i]) & 0xff;

            if ((comp > 0) && (comp <= 0x3e))
            {
                // skip forward by comp;
                reg += comp;
                i++;
                mode = 0; // have to keep on reading
            }
            else if (comp == 0x3f)
            {
                // skip forward by the following 16 bit word;
                // second byte is hi-byte of the word
                reg += ((int)nearRLE[i+1]) & 0xff;
                reg += (((int)nearRLE[i+2]) & 0xff) << 8;

                i+=3;
            }
            else if (comp == 0xff)
            {
                // include the following WORD of regions
                mode = ((int)nearRLE[i+1]) & 0xff;
                mode += (((int)nearRLE[i+2]) & 0xff) << 8;
                i += 3;
            }
            else if ((comp >= 0xc0) && (comp <= 0xfe))
            {
                // comp - 0xc0 regions are nearby
                mode = comp - 0xc0;  // +1 perhaps?
                i++;
            }
            else if ((comp >= 0x40) && (comp <= 0x7f))
            {
                // skip bits 3-5 IDs and then include bits 0-2
                reg += (comp & 0x38) >> 3;
                mode = (comp & 0x7);
                i++;
            }
            else if ((comp >= 0x80) && (comp <= 0xbf))
            {
                // include IDs bits 3-5, then skip bits 0-2
                mode = (comp & 0x38) >> 3;
                skip = (comp & 0x7);
                i++;
            }
        }
    }

    public boolean hasNext()
    {
        // not at the end of the RLE, and not currently processing a
        // directive. (mode)
        return (mode > 0);
    }

    public int next()
    {
        int ret = -1;
        int comp;

        // sanity check first. Shouldn't truthfully get called if mode
        // isn't >0
        if (mode <= 0)
            return -1;

        ret = reg;
        reg++;
        mode--;

        if (mode == 0)
        {
            // skip forward
            reg += skip;
            skip = 0;

            while ((mode == 0) && (i<nearRLE.length))
            {
                // set up the next code
                comp = ((int)nearRLE[i]) & 0xff;

                if ((comp > 0) && (comp <= 0x3e))
                {
                    // skip forward by comp;
                    reg += comp;
                    i++;
                    mode = 0; // have to keep on reading
                }
                else if (comp == 0x3f)
                {
                    // skip forward by the following 16 bit word;
                    // second byte is hi-byte of the word
                    reg += ((int)nearRLE[i+1]) & 0xff;
                    reg += (((int)nearRLE[i+2]) & 0xff) << 8;

                    i+=3;
                }
                else if (comp == 0xff)
                {
                    // include the following WORD of regions
                    mode = ((int)nearRLE[i+1]) & 0xff;
                    mode += (((int)nearRLE[i+2]) & 0xff) << 8;
                    i += 3;
                }
                else if ((comp >= 0xc0) && (comp <= 0xfe))
                {
                    // comp - 0xc0 regions are nearby
                    mode = comp - 0xc0;  // +1 perhaps?
                    i++;
                }
                else if ((comp >= 0x40) && (comp <= 0x7f))
                {
                    // skip bits 3-5 IDs and then include bits 0-2
                    reg += (comp & 0x38) >> 3;
                    mode = (comp & 0x7);
                    i++;
                }
                else if ((comp >= 0x80) && (comp <= 0xbf))
                {
                    // include IDs bits 3-5, then skip bits 0-2
                    mode = (comp & 0x38) >> 3;
                    skip = (comp & 0x7);
                    i++;
                }
            }
        }

        return ret;
    }
}

同样,任何关于如何在C++中适合单个函数(如果可能)的方案的帮助都会很棒.谢谢!

Answer 1

您对 C++ 迭代器有多熟悉？它们的设计看起来非常像指针，因此给定一个迭代器it：

++it

将增加迭代器（跳到下一个元素）

*it

将取消引用迭代器（返回对其指向的元素的引用）

--it

将（如果已定义）递减迭代器（返回到前一个元素）

一般来说，C++ 迭代器对它们所操作的容器一无所知。特别是，检查序列中是否还有更多元素的方法不是调用HasNext迭代器，而是将其与您知道指向序列末尾的迭代器进行比较。（或者，严格来说，将其与指向序列末尾的元素进行比较。）

除此之外，迭代器需要定义一些 typedef 和其他辅助内容，以帮助编译器分类和理解迭代器的功能。

定义迭代器的最简单方法是使用 Boost.Iterator 库的iterator_facade类，它为您实现了几乎所有的管道。该库拥有出色的文档，包括描述如何定义您自己的迭代器类型的教程。

如果可以选择使用 Boost，那么您绝对应该这样做。否则，标准库std::iterator也有一点帮助（但是，值得注意的是，这不是强制性的——可以完美有效地定义迭代器，而无需从此类派生）

很抱歉我没有写出完整的示例，但我现在有点着急。（而且，如果您能够使用 Boost，那么从头开始定义示例迭代器的麻烦就是浪费时间）。希望以上内容足以帮助您入门。