Jos*_*eph 2 javascript ecmascript-6 ecmascript-2016
我需要检查状态是否被批准,所以我检查它是否为空。最有效的方法是什么?
回复
{
"id": 2,
"email": "yeah@yahoo.com",
"approved": {
"approved_at": "2020"
},
"verified": {
"verified_at": "2020"
}
}
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代码
const checkIfEmpty = (user) => {
if (Object.entries(user.verified).length === 0) {
return true;
}
return false;
};
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你可以这样做
const checkIfVerifiedExists = (user) => {
if (user && user.verified && Object.keys(user.verified).length) {
return true;
}
return false;
};
console.log(checkIfVerifiedExists(null));
console.log(checkIfVerifiedExists({something: "a"}));
console.log(checkIfVerifiedExists({verified: null}));
console.log(checkIfVerifiedExists({verified: ""}));
console.log(checkIfVerifiedExists({verified: "a"}));
console.log(checkIfVerifiedExists({verified: "a", something: "b"}));Run Code Online (Sandbox Code Playgroud)
或者更简单您可以使用三元运算符
const checkIfVerifiedExists = (user) => {
return (user && user.verified && Object.keys(user.verified).length) ? true : false
};
console.log(checkIfVerifiedExists(null));
console.log(checkIfVerifiedExists({something: "a"}));
console.log(checkIfVerifiedExists({verified: null}));
console.log(checkIfVerifiedExists({verified: ""}));
console.log(checkIfVerifiedExists({verified: "a"}));
console.log(checkIfVerifiedExists({verified: "a", something: "b"}));Run Code Online (Sandbox Code Playgroud)
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