返回id并拆分逗号分隔值的SQL语句

Question

我有一个包含以下数据的表:

NodeId ExternalIds
50     601
56     700,701

如何编写一个SQL语句,它拆分ExternalIds-column并返回:

NodeId ExternalIds
50     601
56     700
56     701

我找到了很多用户定义的函数和过程,它们将一个字符串拆分成一个表,但我无法让它们中的任何一个工作

编辑

create table #tmpTable (NodeId int, ExternalIds varchar(50))
insert into #tmpTable (NodeId,ExternalIds) values (50, '600')
insert into #tmpTable (NodeId,ExternalIds) values (56, '700,701')

select NodeId, 
    (SELECT * FROM [dbo].[SplitString](select * from #tmpTable,',') where NodeId=56)from #tmpTable)
where NodeId=56
drop table #tmpTable

其中SplitString基于以下内容:

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO

Create FUNCTION [dbo].[SplitString] 
(
    -- Add the parameters for the function here
    @myString varchar(500),
    @deliminator varchar(10)
)
RETURNS 
@ReturnTable TABLE 
(
    -- Add the column definitions for the TABLE variable here
    [id] [int] IDENTITY(1,1) NOT NULL,
    [part] [varchar](50) NULL
)
AS
BEGIN
        Declare @iSpaces int
        Declare @part varchar(50)

        --initialize spaces
        Select @iSpaces = charindex(@deliminator,@myString,0)
        While @iSpaces > 0

        Begin
            Select @part = substring(@myString,0,charindex(@deliminator,@myString,0))

            Insert Into @ReturnTable(part)
            Select @part

    Select @myString = substring(@mystring,charindex(@deliminator,@myString,0)+ len(@deliminator),len(@myString) - charindex(' ',@myString,0))


            Select @iSpaces = charindex(@deliminator,@myString,0)
        end

        If len(@myString) > 0
            Insert Into @ReturnTable
            Select @myString

    RETURN 
END

我试图从Umbraco(cms)的数据库中获取一些数据,这些数据是用逗号分隔的值设计的.

谢谢托马斯

Answer 1

select NodeId, 
       S.part
from #tmpTable
  cross apply [dbo].[SplitString](ExternalIds, ',') as S