Pra*_* T. 5 python http-post httprequest pydantic fastapi
我有一个 POST FastAPI 方法。我不想构造类或查询字符串。所以,我决定应用Body()方法。
@app.post("/test-single-int")
async def test_single_int(
t: int = Body(...)
):
pass
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这是请求
POST http://localhost:8000/test-single-int/
{
"t": 10
}
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这是回应
HTTP/1.1 422 Unprocessable Entity
date: Fri, 22 May 2020 10:00:16 GMT
server: uvicorn
content-length: 83
content-type: application/json
connection: close
{
"detail": [
{
"loc": [
"body",
"s"
],
"msg": "str type expected",
"type": "type_error.str"
}
]
}
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但是,在尝试了许多样本后,我发现如果我有多个Body(). 例如,
POST http://localhost:8000/test-single-int/
{
"t": 10
}
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要求
POST http://localhost:8000/test-multi-mix/
{
"s": "test",
"t": 10
}
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回复
HTTP/1.1 200 OK
date: Fri, 22 May 2020 10:16:12 GMT
server: uvicorn
content-length: 4
content-type: application/json
connection: close
null
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有没有人对我的实现有任何想法?有错吗?这不是最佳实践吗?或者这是一个错误?
这不是错误,而是 Body 的行为方式,它存在用于“扩展”请求参数文档如何概述:
class Item(BaseModel):
name: str
class User(BaseModel):
username: str
full_name: str = None
@app.put("/items/{item_id}")
async def update_item(
*,
item_id: int,
item: Item,
user: User,
importance: int = Body(..., gt=0),
q: str = None
):
pass
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此视图的有效请求正文为:
{
"item": {
"name": "Foo",
"tax": 3.2
},
"user": {
"username": "dave",
"full_name": "Dave Grohl"
},
"importance": 5
}
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如果你真的想单独使用 Body ,你必须指定embed=True,这个按预期工作:
@app.put("/items/{item_id}")
async def update_item(
*,
item_id:int,
importance: int = Body(..., gt=0, embed=True),
q: str = None
):
pass
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