Nik*_*kSp 4 python apache-spark pyspark azure-data-lake databricks
我正在运行以下代码:
list_of_paths 是一个包含以 avro 文件结尾的路径的列表。例如,
['folder_1/folder_2/0/2020/05/15/10/41/08.avro', 'folder_1/folder_2/0/2020/05/15/11/41/08.avro', 'folder_1/folder_2/0/2020/05/15/12/41/08.avro']
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注意:以上路径存储在Azure Data Lake存储中,以下过程在Databricks中执行
spark.conf.set("fs.azure.account.key.{0}.dfs.core.windows.net".format(storage_account_name), storage_account_key)
spark.conf.set("spark.sql.execution.arrow.enabled", "false")
begin_time = time.time()
for i in range(len(list_of_paths)):
try:
read_avro_data,avro_decoded=None,None
#Read paths from Azure Data Lake "abfss"
read_avro_data=spark.read.format("avro").load("abfss://{0}@{1}.dfs.core.windows.net/{2}".format(storage_container_name, storage_account_name, list_of_paths[i]))
except Exception as e:
custom_log(e)
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模式
read_avro_data.printSchema()
root
|-- SequenceNumber: long (nullable = true)
|-- Offset: string (nullable = true)
|-- EnqueuedTimeUtc: string (nullable = true)
|-- SystemProperties: map (nullable = true)
| |-- key: string
| |-- value: struct (valueContainsNull = true)
| | |-- member0: long (nullable = true)
| | |-- member1: double (nullable = true)
| | |-- member2: string (nullable = true)
| | |-- member3: binary (nullable = true)
|-- Properties: map (nullable = true)
| |-- key: string
| |-- value: struct (valueContainsNull = true)
| | |-- member0: long (nullable = true)
| | |-- member1: double (nullable = true)
| | |-- member2: string (nullable = true)
| | |-- member3: binary (nullable = true)
|-- Body: binary (nullable = true)
# this is the content of the AVRO file.
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行数和列数
print("ROWS: ", read_avro_data.count(), ", NUMBER OF COLUMNS: ", len(read_avro_data.columns))
ROWS: 2 , NUMBER OF COLUMNS: 6
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我想要的不是每次迭代读取 1 个 AVRO 文件,因此一次迭代读取 2 行内容。相反,我想一次读取所有 AVRO 文件。所以我的最终 Spark DataFrame 中有 2x3 = 6 行内容。
这对于spark.read()可行吗?像下面这样:
spark.read.format("avro").load("abfss://{0}@{1}.dfs.core.windows.net/folder_1/folder_2/0/2020/05/15/*")
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[更新] 抱歉对通配符(*)的误解。这意味着所有 AVRO 文件都位于同一文件夹中。相反,我每个 AVRO 文件有 1 个文件夹。所以 3 个 AVRO 文件,3 个文件夹。在这种情况下,通配符将不起作用。下面回答的解决方案是使用带有路径名的列表 []。
预先感谢您的帮助和建议。
load(path=None, format=None, schema=None, **options)此方法将接受单个路径或路径列表。
例如,您可以直接传递路径列表,如下所示
spark.read.format("avro").load(["/tmp/dataa/userdata1.avro","/tmp/dataa/userdata2.avro"]).count()
1998
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