我有一个RelativeLayout包含两个按钮.它们相互重叠.
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:background="#FFFFFF">
<Button android:text="Play"
android:id="@+id/play"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:layout_alignParentBottom = "true">
</Button>
<Button android:text="Stop "
android:id="@+id/stop"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:layout_alignParentBottom = "true">
</Button>
</RelativeLayout>
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我想以编程方式一次只显示一个按钮,同时调用其click事件.
我尝试过:
playButton.setVisibility(1);
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但它不起作用.以下是我想要做的一个例子.
playButton = (Button) findViewById(R.id.play);
playButton.setVisibility(1);
playButton.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
//when play is clicked show stop button and hide play button
}
});
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Sun*_*hoo 292
您可以使用以下代码:
playButton = (Button) findViewById(R.id.play);
playButton.setVisibility(View.VISIBLE);
playButton.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
//when play is clicked show stop button and hide play button
playButton.setVisibility(View.GONE);
stopButton.setVisibility(View.VISIBLE);
}
});
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Bal*_*i.K 72
试试下面的代码 -
playButton.setVisibility(View.INVISIBLE);
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要么 -
playButton.setVisibility(View.GONE);
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再次展示 -
playButton.setVisibility(View.VISIBLE);
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Hidde:
BUTTON.setVisibility(View.GONE);
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节目:
BUTTON.setVisibility(View.VISIBLE);
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小智 5
public void OnClick(View.v)
Button b1 = (Button) findViewById(R.id.playButton);
b1.setVisiblity(View.INVISIBLE);
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