Tom*_*ski 0 python loops nested-lists
您好我有一个循环,它会计算我的MySQL数据库中的不同记录,然后将数字保存到列表中.这是清单:
[1L, 2L, 2L, 5L, 4L, 1L, 1L, 1L, 3L, 1L, 1L, 2L, 2L, 3L, 3L, 1L, 2L, 4L, 2L, 1L, 3L, 1L, 2L, 4L, 1L, 2L, 1L, 1L, 3L, 1L, 3L, 1L, 5L, 2L, 1L, 1L, 5L, 1L, 1L, 1L, 4L, 2L, 1L, 3L, 2L, 1L, 2L, 2L, 2L, 3L, 1L, 1L, 3L, 2L, 2L, 1L, 3L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 1L, 3L, 3L, 1L, 2L, 1L, 1L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L]
现在我通过这个列表,我想只留下一个数字(意思是1L,2L等)我正在使用这个循环: for number in legend:
print number # to check what number it does currently
counter = legend.count(number)
while counter > 1:
legend.remove(number)
counter -= 1
这意味着它有效,但为什么它不适合5号?
thx提前
把它放进去吧set.
>>> foo = [1,1,1,2,2,3,3,4,1,4,3,6,5,6]
>>> set(foo)
set([1, 2, 3, 4, 5, 6])
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这将自动过滤掉所有重复项.也许你甚至可以跳过列表,并把它放在一个set位置.