如何正确利用 FastAPI 路由中的异步功能?
以下代码片段需要 10 秒才能完成对我的/home路由的调用,而我预计只需要 5 秒。
from fastapi import FastAPI
import time
app = FastAPI()
async def my_func_1():
"""
my func 1
"""
print('Func1 started..!!')
time.sleep(5)
print('Func1 ended..!!')
return 'a..!!'
async def my_func_2():
"""
my func 2
"""
print('Func2 started..!!')
time.sleep(5)
print('Func2 ended..!!')
return 'b..!!'
@app.get("/home")
async def root():
"""
my home route
"""
start = time.time()
a = await my_func_1()
b = await my_func_2()
end = time.time()
print('It took {} seconds to finish execution.'.format(round(end-start)))
return {
'a': a,
'b': b
}
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我得到以下结果,看起来是非异步的:
? uvicorn fapi_test:app --reload
INFO: Uvicorn running on http://127.0.0.1:8000 (Press CTRL+C to quit)
INFO: Started reloader process [5116]
INFO: Started server process [7780]
INFO: Waiting for application startup.
INFO: Application startup complete.
INFO: 127.0.0.1:51862 - "GET / HTTP/1.1" 404
Func1 started..!!
Func1 ended..!!
Func2 started..!!
Func2 ended..!!
It took 10 seconds to finish execution.
INFO: 127.0.0.1:51868 - "GET /home HTTP/1.1" 200
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但是,我希望 FastAPI 打印如下:
Func1 started..!!
Func2 started..!!
Func1 ended..!!
Func2 ended..!!
It took 5 seconds to finish execution.
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如果我做错了什么,请纠正我?
Mat*_*rna 23
也许有点晚了,根据上面Hedde 的回复进行了详细阐述,您的代码应用程序如下所示。请记住await在睡觉时收集等待任务 - 如果您不这样做,无论您是否使用time.sleep(),都不会asyncio.sleep()同时运行这两个任务。
from fastapi import FastAPI
import time
import asyncio
app = FastAPI()
async def my_func_1():
"""
my func 1
"""
print('Func1 started..!!')
await asyncio.sleep(5)
print('Func1 ended..!!')
return 'a..!!'
async def my_func_2():
"""
my func 2
"""
print('Func2 started..!!')
await asyncio.sleep(5)
print('Func2 ended..!!')
return 'b..!!'
@app.get("/home")
async def root():
"""
my home route
"""
start = time.time()
futures = [my_func_1(), my_func_2()]
a,b = await asyncio.gather(*futures)
end = time.time()
print('It took {} seconds to finish execution.'.format(round(end-start)))
return {
'a': a,
'b': b
}
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