std::chrono::years 存储真的至少是 17 位吗?

san*_*orn 14 c++ libc++ c++-chrono c++20

来自cppreference

std::chrono::years (since C++20) duration</*signed integer type of at least 17 bits*/, std::ratio<31556952>>

使用libc++,似乎std::chrono::yearsis的下划线存储是short有符号的16 位

std::chrono::years( 30797 )        // yields  32767/01/01
std::chrono::years( 30797 ) + 365d // yields -32768/01/01 apparently UB
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cppreference或其他任何内容是否有错别字?

例子:

#include <fmt/format.h>
#include <chrono>

template <>
struct fmt::formatter<std::chrono::year_month_day> {
  char presentation = 'F';

  constexpr auto parse(format_parse_context& ctx) {
    auto it = ctx.begin(), end = ctx.end();
    if (it != end && *it == 'F') presentation = *it++;

#   ifdef __exception
    if (it != end && *it != '}') {
      throw format_error("invalid format");
    }
#   endif

    return it;
  }

  template <typename FormatContext>
  auto format(const std::chrono::year_month_day& ymd, FormatContext& ctx) {
    int year(ymd.year() );
    unsigned month(ymd.month() );
    unsigned day(ymd.day() );
    return format_to(
        ctx.out(),
        "{:#6}/{:#02}/{:#02}",
        year, month, day);
  }
};

using days = std::chrono::duration<int32_t, std::ratio<86400> >;
using sys_day = std::chrono::time_point<std::chrono::system_clock, std::chrono::duration<int32_t, std::ratio<86400> >>;

template<typename D>
using sys_time = std::chrono::time_point<std::chrono::system_clock, D>;
using sys_day2 = sys_time<days>;

int main()
{
  auto a = std::chrono::year_month_day( 
    sys_day( 
      std::chrono::floor<days>(
        std::chrono::hours( (1<<23) - 1 ) 
      )
    )
  );

  auto b = std::chrono::year_month_day( 
    sys_day( 
      std::chrono::floor<days>(
        std::chrono::minutes( (1l<<29) - 1 ) 
      )
    )
  );

  auto c = std::chrono::year_month_day( 
    sys_day( 
      std::chrono::floor<days>(
        std::chrono::seconds( (1l<<35) - 1 ) 
      )
    )
  );

  auto e = std::chrono::year_month_day( 
    sys_day( 
      std::chrono::floor<days>(
        std::chrono::days( (1<<25) - 1 ) 
      )
    )
  );

  auto f = std::chrono::year_month_day( 
    sys_day( 
      std::chrono::floor<days>(
        std::chrono::weeks( (1<<22) - 1 ) 
      )
    )
  );

  auto g = std::chrono::year_month_day( 
    sys_day( 
      std::chrono::floor<days>(
        std::chrono::months( (1<<20) - 1 ) 
      )
    )
  );

  auto h = std::chrono::year_month_day( 
    sys_day( 
      std::chrono::floor<days>(
        std::chrono::years( 30797 ) // 0x7FFF - 1970
      )
    )
  );

  auto i = std::chrono::year_month_day( 
    sys_day( 
      std::chrono::floor<days>(
        std::chrono::years( 30797 ) // 0x7FFF - 1970
      ) + std::chrono::days(365)
    )
  );

  fmt::print("Calendar limit by duration's underlining storage:\n"
             "23 bit hour       : {:F}\n"
             "29 bit minute     : {:F}\n"
             "35 bit second     : {:F}\n"
             "25 bit days       : {:F}\n"
             "22 bit week       : {:F}\n"
             "20 bit month      : {:F}\n"
             "16? bit year      : {:F}\n"
             "16? bit year+365d : {:F}\n"
             , a, b, c, e, f, g, h, i);
}
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[神箭链接]

And*_*hev 8

cppreference 文章是正确的。如果 libc++ 使用较小的类型,那么这似乎是 libc++ 中的错误。

  • @sandthorn `year_month_day` 包含 `year`,而不是 `years`。虽然使用类型“short”作为说明,但“year”的表示形式不需要是 16 位。OTOH,“years”定义中的 17 位部分是规范性的,因为它不被标记为仅说明。坦率地说,说它至少有 17 位,然后不要求它是没有意义的。 (3认同)