删除嵌套数组的一个级别

Question

你怎么能改变这个数组:

[["1","one"], ["2","two"], ["3","three"]]

这个？

["1","one"], ["2","two"], ["3","three"]

澄清

对于提供无效的第二版我道歉.这就是我真正想要的:

我想添加["0","zero"]到开头[["1","one"], ["2","two"], ["3","three"]],获取:

[["0","zero"], ["1","one"], ["2","two"], ["3","three"]]

我试过了:

["0","zero"] << [["1","one"], ["2","two"], ["3","three"]]

上面的方法产生了这个,它包含一个我不想要的嵌套:

[["0","zero"], [["1","one"], ["2","two"], ["3","three"]]]

Answer 1

unshift 应该为你做:

a = [["1","one"], ["2","two"], ["3","three"]]
a.unshift(["0", "zero"])
=> [["0", "zero"], ["1", "one"], ["2", "two"], ["3", "three"]]

Answer 2

您可能正在寻找flatten：

返回一个新数组，该数组是该数组的一维展平（递归地）。也就是说，对于数组中的每个元素，将其元素提取到新数组中。如果可选的 level 参数确定要展平的递归级别。

[["1","one"], ["2","two"], ["3","three"]].flatten

这给你：

=> ["1", "one", "2", "two", "3", "three"]